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Exercise 2 In all the problem, the liaison and the decoupling are perfect in variable mode. The transistors used in the circuits are identical and are characterized by: h11 = 2.8k, h21e = B = 300,h12e = h22e = 0. We consider the assembly of figure 2. Ve is delivered by a sine voltage generator and Vcc=12V, RE = 2.2k. 1- In continuous regime, we impose for this circuit: VBE = 0.7V, VCE = 1/2 RB Cel Rc RE Figure 2: 15 A Vcc Rul V₁ 6V, Ic= 2,82 mA. find Rc and RB. Draw in the plane Ic, Vce the lines of static and dynamic load. For what value of VCE is the transistor blocked (Ic = 0). Determine the power dissipated in the transistor when it is blocked. 1/2

Exercise 2 In all the problem, the liaison and the decoupling are perfect in variable mode. The transistors used in the circuits are identical and are characterized by: h11 = 2.8k, h21e = B = 300,h12e = h22e = 0. We consider the assembly of figure 2. Ve is delivered by a sine voltage generator and Vcc=12V, RE = 2.2k. 1- In continuous regime, we impose for this circuit: VBE = 0.7V, VCE = 1/2 RB Cel Rc RE Figure 2: 15 A Vcc Rul V₁ 6V, Ic= 2,82 mA. find Rc and RB. Draw in the plane Ic, Vce the lines of static and dynamic load. For what value of VCE is the transistor blocked (Ic = 0). Determine the power dissipated in the transistor when it is blocked. 1/2

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Exercise 2 part 1

to 2 v and EBM Corresponding to the maximum possible variation determined in ques 5. What can we deduce from this? Exercise 2 In all the problem, the liaison and the decoupling are perfect in variable mode. The transistors used in the circuits are identical and are characterized by: h₁1 = 2.8k, h₂1e B = 300, h12e = h22e = 0. We consider the assembly of figure 2. Ve is delivered by a sine voltage generator and Vcc=12V, RE = 2.2kQ. 1- In continuous regime, we impose for this circuit: VBE = 0.7V, VCE = = 1/2 RB Cel HH Rc RE Figure 2: Cst A Vcc 6V, Ic= 2,82 mA. find Rc and R³. Draw in the plane Ic, Vce the lines of static and dynamic load. For what value of VCE is the transistor blocked (Ic = 0). Determine the power dissipated in the transistor when it is blocked. 2- Why is this assembly called a common transmitter? 3- After recalling the equivalent diagram of the transistor in small signal mode, assuming that h₁2e = h₂2 = 0, give the equivalent diagram of the alternating circuit for small sinusoidal signals. = Deduce the expression and the numerical value of: 1.1. The input resistance Re. Deduce that Re is of the order of h₁1 · 1.2. The gain Avo at free load (load Ru₁ infinite) 3.3kΩ and Ru1 1.3. The gain A₂ for a load Rul 1.4. The composite gain A'=V₁/V2. 1.5. The output resistance Rs. = 32kN. Conclude Rul V₁ 1/2
Transcribed Image Text:to 2 v and EBM Corresponding to the maximum possible variation determined in ques 5. What can we deduce from this? Exercise 2 In all the problem, the liaison and the decoupling are perfect in variable mode. The transistors used in the circuits are identical and are characterized by: h₁1 = 2.8k, h₂1e B = 300, h12e = h22e = 0. We consider the assembly of figure 2. Ve is delivered by a sine voltage generator and Vcc=12V, RE = 2.2kQ. 1- In continuous regime, we impose for this circuit: VBE = 0.7V, VCE = = 1/2 RB Cel HH Rc RE Figure 2: Cst A Vcc 6V, Ic= 2,82 mA. find Rc and R³. Draw in the plane Ic, Vce the lines of static and dynamic load. For what value of VCE is the transistor blocked (Ic = 0). Determine the power dissipated in the transistor when it is blocked. 2- Why is this assembly called a common transmitter? 3- After recalling the equivalent diagram of the transistor in small signal mode, assuming that h₁2e = h₂2 = 0, give the equivalent diagram of the alternating circuit for small sinusoidal signals. = Deduce the expression and the numerical value of: 1.1. The input resistance Re. Deduce that Re is of the order of h₁1 · 1.2. The gain Avo at free load (load Ru₁ infinite) 3.3kΩ and Ru1 1.3. The gain A₂ for a load Rul 1.4. The composite gain A'=V₁/V2. 1.5. The output resistance Rs. = 32kN. Conclude Rul V₁ 1/2
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