Exercise 2 In all the problem, the liaison and the decoupling are perfect in variable mode. The transistors used in the circuits are identical and are characterized by: h11 = 2.8k, h21e = B = 300,h12e = h22e = 0. We consider the assembly of figure 2. Ve is delivered by a sine voltage generator and Vcc=12V, RE = 2.2k. 1- In continuous regime, we impose for this circuit: VBE = 0.7V, VCE = 1/2 RB Cel Rc RE Figure 2: 15 A Vcc Rul V₁ 6V, Ic= 2,82 mA. find Rc and RB. Draw in the plane Ic, Vce the lines of static and dynamic load. For what value of VCE is the transistor blocked (Ic = 0). Determine the power dissipated in the transistor when it is blocked. 1/2
Exercise 2 In all the problem, the liaison and the decoupling are perfect in variable mode. The transistors used in the circuits are identical and are characterized by: h11 = 2.8k, h21e = B = 300,h12e = h22e = 0. We consider the assembly of figure 2. Ve is delivered by a sine voltage generator and Vcc=12V, RE = 2.2k. 1- In continuous regime, we impose for this circuit: VBE = 0.7V, VCE = 1/2 RB Cel Rc RE Figure 2: 15 A Vcc Rul V₁ 6V, Ic= 2,82 mA. find Rc and RB. Draw in the plane Ic, Vce the lines of static and dynamic load. For what value of VCE is the transistor blocked (Ic = 0). Determine the power dissipated in the transistor when it is blocked. 1/2
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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Exercise 2 part 1
![to 2 v and EBM Corresponding to the maximum possible variation determined in ques
5. What can we deduce from this?
Exercise 2
In all the problem, the liaison and the
decoupling are perfect in variable mode.
The transistors used in the circuits are
identical and are characterized by:
h₁1 = 2.8k, h₂1e B = 300, h12e = h22e =
0.
We consider the assembly of figure 2. Ve
is delivered by a sine voltage generator
and Vcc=12V, RE = 2.2kQ.
1- In continuous regime, we impose
for this circuit: VBE = 0.7V, VCE
=
=
1/2
RB
Cel
HH
Rc
RE
Figure 2:
Cst
A Vcc
6V, Ic= 2,82 mA.
find Rc and R³. Draw in the plane Ic, Vce the lines of static and dynamic load.
For what value of VCE is the transistor blocked (Ic = 0). Determine the power
dissipated in the transistor when it is blocked.
2- Why is this assembly called a common transmitter?
3- After recalling the equivalent diagram of the transistor in small signal
mode, assuming that h₁2e = h₂2 = 0, give the equivalent diagram of the
alternating circuit for small sinusoidal signals.
=
Deduce the expression and the numerical value of:
1.1. The input resistance Re. Deduce that Re is of the order of h₁1 ·
1.2. The gain Avo at free load (load Ru₁ infinite)
3.3kΩ and Ru1
1.3. The gain A₂ for a load Rul
1.4. The composite gain A'=V₁/V2.
1.5.
The output resistance Rs.
= 32kN. Conclude
Rul V₁
1/2](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe53828e0-fbca-4901-a6df-51fa058b3532%2F8b0217db-4b4a-4965-91be-2eadeee40e73%2F04mkpoi_processed.jpeg&w=3840&q=75)
Transcribed Image Text:to 2 v and EBM Corresponding to the maximum possible variation determined in ques
5. What can we deduce from this?
Exercise 2
In all the problem, the liaison and the
decoupling are perfect in variable mode.
The transistors used in the circuits are
identical and are characterized by:
h₁1 = 2.8k, h₂1e B = 300, h12e = h22e =
0.
We consider the assembly of figure 2. Ve
is delivered by a sine voltage generator
and Vcc=12V, RE = 2.2kQ.
1- In continuous regime, we impose
for this circuit: VBE = 0.7V, VCE
=
=
1/2
RB
Cel
HH
Rc
RE
Figure 2:
Cst
A Vcc
6V, Ic= 2,82 mA.
find Rc and R³. Draw in the plane Ic, Vce the lines of static and dynamic load.
For what value of VCE is the transistor blocked (Ic = 0). Determine the power
dissipated in the transistor when it is blocked.
2- Why is this assembly called a common transmitter?
3- After recalling the equivalent diagram of the transistor in small signal
mode, assuming that h₁2e = h₂2 = 0, give the equivalent diagram of the
alternating circuit for small sinusoidal signals.
=
Deduce the expression and the numerical value of:
1.1. The input resistance Re. Deduce that Re is of the order of h₁1 ·
1.2. The gain Avo at free load (load Ru₁ infinite)
3.3kΩ and Ru1
1.3. The gain A₂ for a load Rul
1.4. The composite gain A'=V₁/V2.
1.5.
The output resistance Rs.
= 32kN. Conclude
Rul V₁
1/2
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