Exercise 2: According to an appliance manufacturer, the 4-in,-diameter vent on a clothes dryer is not to contain more than 20 ft of pipe and four 90° elbows. Under these conditions determine the air volumetric flow rate if the gage pressure within the dryer is 0.20 inches of water. Assume both the specific weight and the kinematic viscosity of the heated air to be constant and equal to y0.0709 bf/t, and v-wp=1.79x10-4 ft2/s, respectively, and that the roughness of the vent pipe surface is equivalent to that of galvanized iron. (2) Figure K: Schematic for Exercise 2. Moran&Shapiro, 2002
Exercise 2: According to an appliance manufacturer, the 4-in,-diameter vent on a clothes dryer is not to contain more than 20 ft of pipe and four 90° elbows. Under these conditions determine the air volumetric flow rate if the gage pressure within the dryer is 0.20 inches of water. Assume both the specific weight and the kinematic viscosity of the heated air to be constant and equal to y0.0709 bf/t, and v-wp=1.79x10-4 ft2/s, respectively, and that the roughness of the vent pipe surface is equivalent to that of galvanized iron. (2) Figure K: Schematic for Exercise 2. Moran&Shapiro, 2002
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:Exercise 2: According to an appliance manufacturer, the 4-in.-diameter vent on a clothes dryer is not to contain more than 20
ft of pipe and four 90° elbows. Under these conditions determine the air volumetric flow rate if the gage pressure within the
dryer is 0.20 inches of water. Assume both the specific weight and the kinematic viscosity of the heated air to be constant and
equal to
y=0.0709 bf/ft?, and
v=µp=1.79x10 -4 ft2/s,
respectively, and that the roughness of the vent pipe surface is equivalent to that of galvanized iron.
C20
0.2 in.
V-0
(2)
Figure K: Schematic for Exercise 2, Moran&Shapiro, 2002
O KFVD) = 3.87
O K fVD)= 3.67)
O K/ (FVD) = 3.79
O K/ (FVD) = 3.74
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