Exercise 1. The on-axis magnetic field due to a circular current loop of radius R lying flat in the x-y plane, centered at the origin, and carrying current / is given by Equation 1. We will take this formula for granted today and derive it officially next week. B₂ = Show that Equation 1 is equivalent to Express Bo in terms of Mo, R, and I. What is Bo for I=200A and R=0.1 m? Ho I 2πR² 4π (R²+z²)3/2 B₂ R³ = = Bo (R² + z²)3/2 where Bo is the magnetic field at the center of the loop. (1) Graph B₂ as a function of z from z=-2R to z=2R (using the numerical values above) in Excel. Make it easy to vary the values of R and I.

Exercise 1. The on-axis magnetic field due to a circular current loop of radius R lying flat in the x-y plane, centered at the origin, and carrying current / is given by Equation 1. We will take this formula for granted today and derive it officially next week. B₂ = Show that Equation 1 is equivalent to Express Bo in terms of Mo, R, and I. What is Bo for I=200A and R=0.1 m? Ho I 2πR² 4π (R²+z²)3/2 B₂ R³ = = Bo (R² + z²)3/2 where Bo is the magnetic field at the center of the loop. (1) Graph B₂ as a function of z from z=-2R to z=2R (using the numerical values above) in Excel. Make it easy to vary the values of R and I.