A proton is observed to move on a circular orbit of radiusr = 14cmin a uniform magnetic field having an intensity equal to 0.35 T What tangential velocity does the proton have? (proton mass = 1.67 x 10 2 kg. proton charge = 1.6 × 10-19 C). = Mo1) O = 2.66 x 10°m/s O (by = 4.69 x 10°m/s O (C)v = 2.34 x 10°m/s O (dv = 1.33 x 10°m/s
A proton is observed to move on a circular orbit of radiusr = 14cmin a uniform magnetic field having an intensity equal to 0.35 T What tangential velocity does the proton have? (proton mass = 1.67 x 10 2 kg. proton charge = 1.6 × 10-19 C). = Mo1) O = 2.66 x 10°m/s O (by = 4.69 x 10°m/s O (C)v = 2.34 x 10°m/s O (dv = 1.33 x 10°m/s
Related questions
Question
Please solve asap i'm studying for my test tomorrow and i need the answer

Transcribed Image Text:A proton is observed to move on a circular orbit of radius
r =
14cmin a uniform magnetic field having an intensity equal to 0.35 T.
What tangential velocity does the proton have? (proton mass = 1.67 x 10 2kg. proton charge = 1.6 x 10 19 C).
O (toy = 2.66 × 10°m/s
(b)y = 4.69 x 10°m/s
O (Cv = 2.34 x 10°m/s
O (dv = 1.33 x 10°m/s
Expert Solution

This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 2 steps
