Exemple in 2D motion MX Bike Sand Dune V₁ = 60 mi/h = ? = h₂ = 10 m 10m 0 Problem Setup: MX-Bike is initially moving in horizontal direction. ay (m) → V₂ = Vox 10m ках- m see Vy ? = 60 m Ihr hr 3600 sec ↓= -(9.8 M/²) ĝ ¥> X(m) Хf=range 1610m Imi = 27 m/s Solution Break the motion down into the components in the x-y- directions Hmwk #1 Vox= constant of the motion! Voy= = 0 leaving the dune. 2) ~25m/5 Vox ? v² = √² + 2a(y-Y.) la 1 = ay = 9.8 m/ 5² |y₁|=h₂ = 10m 1) y(t) = y₂ + ₁² + + £a₂t² → sy=h₂ = 1/2a₂t²") t= AX st fy=? ку Q's time in air ? (1) H What is the range? (2) • What is Vy (final) ? (3) Lo Hmuk #1 2h. ~ 2(10m) √2 sec=1.414 sec ay 10 m/s2 27 m/s X~ √x st = (27)(√²1 sα) = ? √2 (27) time in the air . solve fort! m
Exemple in 2D motion MX Bike Sand Dune V₁ = 60 mi/h = ? = h₂ = 10 m 10m 0 Problem Setup: MX-Bike is initially moving in horizontal direction. ay (m) → V₂ = Vox 10m ках- m see Vy ? = 60 m Ihr hr 3600 sec ↓= -(9.8 M/²) ĝ ¥> X(m) Хf=range 1610m Imi = 27 m/s Solution Break the motion down into the components in the x-y- directions Hmwk #1 Vox= constant of the motion! Voy= = 0 leaving the dune. 2) ~25m/5 Vox ? v² = √² + 2a(y-Y.) la 1 = ay = 9.8 m/ 5² |y₁|=h₂ = 10m 1) y(t) = y₂ + ₁² + + £a₂t² → sy=h₂ = 1/2a₂t²") t= AX st fy=? ку Q's time in air ? (1) H What is the range? (2) • What is Vy (final) ? (3) Lo Hmuk #1 2h. ~ 2(10m) √2 sec=1.414 sec ay 10 m/s2 27 m/s X~ √x st = (27)(√²1 sα) = ? √2 (27) time in the air . solve fort! m
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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i just need number 3
![Exemple in 2D motion
- MX Bike/Sand Dune
V₁ = 60 mi/h = ? = " ? =
see
h₂ = 10 m
10m
Problem Setup: MX-Bike is initially
moving in horizontal direction.
y (m)
0
V₂ = Vox
10m
kax.
60 mi Ihr
Vy
hr 3600sec
tā=
à = −(9.8 M/³² ) ĝ
X(m)
X₁ = range
.
1610m = 27 m/s ~25 m/s
Imi
Solution Break the motion down into the components in
the X-, y
directions
Vox= constat of the motion!
Hmwk #1
Voy = 0 leaving the dune.
la1 = ay = 9.8 m/s²
|y₁|=h₂ = 10m
2)
2 ho
ау
Vox
3) Vy
1) y(t) = y₂ + y₂ + + £ a₂t² → sy=h₂ = 1/2a₂+²;
ay t
ayt^)
t=
2(10m)
√√2¹ sec=1.414 sec
solve fort!
1x~ √x st = (27/1) (√²1 sec ) = ?
√2(27) m
AX
st
=?
=
? V² = V₂² + 2a(Y-Y₂)
10m/52
27 m/s
=
Q's time in air ? (1)
what is the range?
.
time in the air
? (2)
Vy(fins 1)? (3)
What is V.
Lo Hmwk #1](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F972a81e1-caa2-41dc-a3c7-a688283b6b6c%2F07e04cce-feed-41ce-9683-e85ec6d46284%2Fpd7p8rj_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Exemple in 2D motion
- MX Bike/Sand Dune
V₁ = 60 mi/h = ? = " ? =
see
h₂ = 10 m
10m
Problem Setup: MX-Bike is initially
moving in horizontal direction.
y (m)
0
V₂ = Vox
10m
kax.
60 mi Ihr
Vy
hr 3600sec
tā=
à = −(9.8 M/³² ) ĝ
X(m)
X₁ = range
.
1610m = 27 m/s ~25 m/s
Imi
Solution Break the motion down into the components in
the X-, y
directions
Vox= constat of the motion!
Hmwk #1
Voy = 0 leaving the dune.
la1 = ay = 9.8 m/s²
|y₁|=h₂ = 10m
2)
2 ho
ау
Vox
3) Vy
1) y(t) = y₂ + y₂ + + £ a₂t² → sy=h₂ = 1/2a₂+²;
ay t
ayt^)
t=
2(10m)
√√2¹ sec=1.414 sec
solve fort!
1x~ √x st = (27/1) (√²1 sec ) = ?
√2(27) m
AX
st
=?
=
? V² = V₂² + 2a(Y-Y₂)
10m/52
27 m/s
=
Q's time in air ? (1)
what is the range?
.
time in the air
? (2)
Vy(fins 1)? (3)
What is V.
Lo Hmwk #1
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