Excercise 40 Prove that the pairwise radical axes of three circles with not collinear centers meet a сотmon point. Hint. Equalities O,p² – rỉ = 02P² – rž and O2P² – r = O3P2 – r? - imply that O1P² – rỉ = O3P² – rž, i.e. the intersection point of the radical axes l12 and l23 is on l13 as well. It is called the radical center of the circles.
Excercise 40 Prove that the pairwise radical axes of three circles with not collinear centers meet a сотmon point. Hint. Equalities O,p² – rỉ = 02P² – rž and O2P² – r = O3P2 – r? - imply that O1P² – rỉ = O3P² – rž, i.e. the intersection point of the radical axes l12 and l23 is on l13 as well. It is called the radical center of the circles.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Let A,B and C be three circles with no collinear centers.
Let be the intersection point and be the radical axis of circles A and B.
Let be the intersection point and be the radical axis of circles B and C
Let be the intersection point and be the radical axis of circles C and A.
Let be the centers of the three circles.
Let P be a point, then the radical axis of circles A and B is defined as the line along which the tangents to those circles are equal in length.
Similarly, the tangents to circles B and C must be equal in length on their radical axis.
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