Q4. equation of circle x² + y² - 6x-2y +6 = 0 2 )2 (x-3)² + (y-13² = 4 circle with center line y = Interesect at two Kx +3 at two point if distance from center is less than 2 Let D denote distance 1 3 K -3 √K ²+1 D = |3K+2) к2+1 |3K+21 √K²+T (3,1) 22 + radius = 2 | 3 K+2 | < 2 √ K³² (3k+232 с иск2+1) 4x² gx²+4+12K < 2 5K² +12K
Q4. equation of circle x² + y² - 6x-2y +6 = 0 2 )2 (x-3)² + (y-13² = 4 circle with center line y = Interesect at two Kx +3 at two point if distance from center is less than 2 Let D denote distance 1 3 K -3 √K ²+1 D = |3K+2) к2+1 |3K+21 √K²+T (3,1) 22 + radius = 2 | 3 K+2 | < 2 √ K³² (3k+232 с иск2+1) 4x² gx²+4+12K < 2 5K² +12K
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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TRANSCRIBE THE FOLLOWING SOLUTION IN DIGITAL FORMAT

Transcribed Image Text:b) Tangents
For tangent
D=
c) other
distance from center to line = 2
| 1-3K-31
√K²+1
13 K+2)
√K²+
= 2
(3K+²²= 2² (K²+1)
9 +²+4+ 12k = 4*2+4
+
= 2
5K² + 12x = 0
K=0, K = -1
.-12
-
+
K ε (-∞, -1²/²-) u (0,00)

Transcribed Image Text:áll
a)
equation of circle
(x-3)² +
)2
x2+y2 -6x-2y +6=0
(y-1)² = 4
Су-1)2
circle with center
y =
Kx +3
line
Interesect at two point if distance from
center is less than 2
Let D denote distance
3K-3/
Sk2+1
(3,1)
radius = 2
D = |3K+2/
√K²+1
|3K+21
√K²4T
| 3K+2) < 2 √ K²+1
(3k+232 с иск2+1)
9к2+4+12k < 4к2
+
22
5K² +12K <O
2
5K (K + ¹2).
<
O
ס.
+
-1/32/33
K ε (-1/²/3, 0)
ке
+4
Expert Solution

Step 1
Note: As per your request, the solution is in digital format is given below.
Q4. Equation of circle
Circle with center (3,1)
radius = 2
Line y = Kx + 3
Step by step
Solved in 4 steps
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