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Example: What is the NBOD, in mg 02/1, of a waste containing 20 mg/L ammonia as nitrogen (NH3-N)? (MW N = 14 g/mol) NH4+ + 202 → NO3 + H2O + 2H+ 14 14 g/mol 2 х 32 рет мое 2015/2 x. (2×12):91MS 145/2 02/1 A. 5 mg g 02/1 My Answer is closest to: B. 45 mg 02/1 C. 91 mg 02/1

Example: What is the NBOD, in mg 02/1, of a waste containing 20 mg/L ammonia as nitrogen (NH3-N)? (MW N = 14 g/mol) NH4+ + 202 → NO3 + H2O + 2H+ 14 14 g/mol 2 х 32 рет мое 2015/2 x. (2×12):91MS 145/2 02/1 A. 5 mg g 02/1 My Answer is closest to: B. 45 mg 02/1 C. 91 mg 02/1

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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The answer is 91

O2 nccded 11 MW 10697mW 9.43× 10-4 moles × 32 × 9.41× 10-4 = .169 = 166 mg " THE UNIVERSITY OF KUKANSAS 10 Problem Example: What is the NBOD, in mg 02/1, of a waste containing 20 mg/L ammonia as nitrogen (NH3-N)? (MW N 14 g/mol) NH4+ + 202 → NO3 + H2O + 2H+ ✓ 14 g/mol 2х32 рет мое 201512 = x. (2x72) = 91m3 14 g/L 9/2 02/1 A. 5 mg g 02/1 My Answer is closest to: B. 45 mg 02/1 C. 91 mg 02/1 THE UNIVERSITY OF KUKANSAS 11 Chemical Oxygen Demand
Transcribed Image Text:O2 nccded 11 MW 10697mW 9.43× 10-4 moles × 32 × 9.41× 10-4 = .169 = 166 mg " THE UNIVERSITY OF KUKANSAS 10 Problem Example: What is the NBOD, in mg 02/1, of a waste containing 20 mg/L ammonia as nitrogen (NH3-N)? (MW N 14 g/mol) NH4+ + 202 → NO3 + H2O + 2H+ ✓ 14 g/mol 2х32 рет мое 201512 = x. (2x72) = 91m3 14 g/L 9/2 02/1 A. 5 mg g 02/1 My Answer is closest to: B. 45 mg 02/1 C. 91 mg 02/1 THE UNIVERSITY OF KUKANSAS 11 Chemical Oxygen Demand
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