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Example Stranded conductor 19/2.9 mm. calculate the equivalent diameter of conductor. Solution: The diameter of one strand (d) = 2.9 mm No. of stranded in conductor (Ns)=27 Therefore for No. of layer = 2, distributed as follow: = [1 + 6+ 12] core 1st layer 2nd layer

Example Stranded conductor 19/2.9 mm. calculate the equivalent diameter of conductor. Solution: The diameter of one strand (d) = 2.9 mm No. of stranded in conductor (Ns)=27 Therefore for No. of layer = 2, distributed as follow: = [1 + 6+ 12] core 1st layer 2nd layer

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Example Stranded conductor 19/2.9 mm. calculate the equivalent diameter of conductor. Solution: The diameter of one strand (d) = 2.9 mm No. of stranded in conductor (Ns) = 27 Therefore for No. of layer = 2, distributed as follow: = [1 + 6+ core 1st layer 12] 2nd layer
Transcribed Image Text:Example Stranded conductor 19/2.9 mm. calculate the equivalent diameter of conductor. Solution: The diameter of one strand (d) = 2.9 mm No. of stranded in conductor (Ns) = 27 Therefore for No. of layer = 2, distributed as follow: = [1 + 6+ core 1st layer 12] 2nd layer
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