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Example: Given the equilibrium constants for the reactions 2 NO(g) ⇒ N₂(g) + O₂(g) 2 NO(g) + O₂(g) 2 NO₂(g) Kc1 = 2.3 x 1024 Kc₂= 6.4 x 10⁹ find the numerical value for Kc3, the equilibrium constant for the reaction N₂(g) + 2 O₂(g) ⇒ 2 NO₂(g) Kc3 ² ? =

Example: Given the equilibrium constants for the reactions 2 NO(g) ⇒ N₂(g) + O₂(g) 2 NO(g) + O₂(g) 2 NO₂(g) Kc1 = 2.3 x 1024 Kc₂= 6.4 x 10⁹ find the numerical value for Kc3, the equilibrium constant for the reaction N₂(g) + 2 O₂(g) ⇒ 2 NO₂(g) Kc3 ² ? =

Chemistry
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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at the very end of the 2nd image. can you elaborate as to how Kc1 was achieved in 1/Kc1 ? I understand how to get the 1, but i dont understand why there is a Kc1 under the 1. The same thing applies to the Kc2 to the right of this. can you elaborate more on this please? 

Example: Given the equilibrium constants for the reactions 2 NO(g) ⇒ N₂(g) + O₂(g) 2 NO(g) + O₂(g) ⇒ 2 NO₂(g) Kc1 = 2.3 x 1024 Kc₂ = 6.4 x 10⁹ find the numerical value for Kc3, the equilibrium constant for the reaction = N₂(g) + 2 O₂(g) ⇒ 2 NO₂(g) Kc3 ?
Transcribed Image Text:Example: Given the equilibrium constants for the reactions 2 NO(g) ⇒ N₂(g) + O₂(g) 2 NO(g) + O₂(g) ⇒ 2 NO₂(g) Kc1 = 2.3 x 1024 Kc₂ = 6.4 x 10⁹ find the numerical value for Kc3, the equilibrium constant for the reaction = N₂(g) + 2 O₂(g) ⇒ 2 NO₂(g) Kc3 ?
2 NO(g) ⇒ N₂(g) + O₂(g) 2 NO(g) + O₂(g) ⇒ 2 NO₂(g) N₂(g) + 2 O₂(g) ⇒ 2 NO₂(g) KC3 [NO₂]² [NO]² [N₂][0₂]² [N₂][0₂] = — Kc1 = [N₂][O₂] = 2.3 x 10²4 [NO]² Kc2 KC3 [NO]²[0₂] — 1 2.3 x 1024 [NO₂]² [NO]²[0₂] [NO₂] = 1 [NO₂]² [N₂][0₂]² = 6.4 x 10⁹ Kcl KC2 (6.4 x 10⁹) = 2.8 x 10-¹5
Transcribed Image Text:2 NO(g) ⇒ N₂(g) + O₂(g) 2 NO(g) + O₂(g) ⇒ 2 NO₂(g) N₂(g) + 2 O₂(g) ⇒ 2 NO₂(g) KC3 [NO₂]² [NO]² [N₂][0₂]² [N₂][0₂] = — Kc1 = [N₂][O₂] = 2.3 x 10²4 [NO]² Kc2 KC3 [NO]²[0₂] — 1 2.3 x 1024 [NO₂]² [NO]²[0₂] [NO₂] = 1 [NO₂]² [N₂][0₂]² = 6.4 x 10⁹ Kcl KC2 (6.4 x 10⁹) = 2.8 x 10-¹5
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But why is KC1 inverted? I still dont understand why. why isn't it just Kc2 x Kc1.

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