Example: A transmission line with a characteristic impedance of 2-502 is terminated with a load of Z₁ = 60- j40-2 a) Find the reflection coefficient at the load. Find the SWR of the line. find the input impedance at 2 = 0.22
Short Transmission Line
A short transmission line is a transmission line that has a length less than 80 kilometers, an operating voltage level of less than 20 kV, and zero capacitance effect.
Power Flow Analysis
Power flow analysis is a topic in power engineering. It is the flow of electric power in a system. The power flow analysis is preliminary used for the various components of Alternating Current (AC) power, such as the voltage, current, real power, reactive power, and voltage angles under given load conditions and is often known as a load flow study or load flow analysis.
Complex Form
A power system is defined as the connection or network of the various components that convert the non-electrical energy into the electric form and supply the electric form of energy from the source to the load. The power system is an important parameter in power engineering and the electrical engineering profession. The powers in the power system are primarily categorized into two types- active power and reactive power.

![RTN LOSS [dB]
REL COE
RFL COEFF, E or 1
SWR
dBS
P
0
990
0.0
Y
A
x
ORIGIN
31
-10040 20
+++
40 30
181
+++++
STO
dydydd
1 0.9 0.8
1
0.9
0.1
0.05
0.05
105++
150
10
0.04 ++
0.46
2
H
+++++
0.44
0.45
0.7
d
&.
10
4444
20
19-
-140
900
0.8
2
0.2
10%!
0.06
0.44
140
0.6
0.43
15
0.07 +++
0.5
0.7
0.43
1.30
70
0,3
1 18
ACTANCE COMPONENT (X/Zo) OR CAPACITIVE SUSCEPTANCE (+B/Ye)
200
+++++++++
-130
4
04
0.04
lett
de
15
0.42
Tal
0.6
0.4
210
4
0.08
CAPACITIVE REACTANCE COMPONENT (-X/Zo), OR INDUCTIVE SUSC
8
TY
5
a
RESISTANCE COMPONENT (R/Zo), OR CONDUCTANCE COMPONENT (G/Yo
102
-120
0.3
120
10
3
+++++++++++++
tro
6
tytritt
0.09 01
0.41
04
0.5
0,5
0₂.
18
The Complete Smith Chart
Black Magic Design
0.09
کر
2.5
2
02
r
110
0.4
0.6
-110
YO
8
78 8 9 10
0.1
9
55
$
0.1
2 1.8 16
+ T
0.3
0.7
3
011
0.39
001-
0.11
0.12
++++++++
H
0.38
02
100
0.8
543
12
14
0.05
14
Sº
8
$
0.12
++++++++0.39
0.9
9
800
1889 2
D
06-
90
15
20
2 111
30-0
00
01
0.01
0.1
2
15
02
to
to
CENTER
YO
10.4
10.4
0.13
0.13
0.37
+++
0.37
10.6
190
1.1
10
10.6
RADIALLY SCALED PARAMETERS
12 11 1 15.
1.1
0.99
0.8
0.6
0.8
HH+++++++++++++++
0.35
10.8
0.8
-50
E
12
Op
10
80
Lo
0.14
0.36
TOWARD LOAD->
1.0
1.1
0.1 0.2
0.14
0.36
12
0.95
13
12
0.4
5
14
0.9
1.3
3
n
16-
0.15
0.35
70
1.5
$
6
14
phopd
9
0.16
13 14
0.6 0.8 1
0.34
0.16
A
ко
T
vo
15
-60
60
&
16 15 2
15
0.17
Myyt
N
0.33
2
16 17 18 19 2
0.8
0.7
017
0.33
1.6
+
20
0.6
0.18
0.18
++
0.32
50
ZEO
17
Myyd
dydydydydydy
++++
3.0
&
49
4
0.31
6
0.4
0.19
++++++++++++++++|||||
05-
40
-40
3
1.8
0.19
0.31
40
TOWARD GENERATOR
hagdangd
3
3
2.5
0.5
Typh
15/40
←
0.3
36
92
30
0.3
lov:
++
10 20
61
Fet
0.29
A
10 15
10->
45
03 02 01 0
ATTEN [dB]
S.W. LOSS COEFF
RFL LOSS [dB]
Tap]
2
S.W. PEAK (CONS"
TRANSM COEFF."
TRANSM COEFF."](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3361ca50-fe39-4902-8c9b-25c25195dd96%2F3b9acc5a-8970-4389-ba77-9dc56bdffaeb%2F1sh08v4_processed.jpeg&w=3840&q=75)

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