Example 9.7: Three single core lead sheathed cables carry three-phase current of 400 A. The nominal conductor area of the cores is 1.25 sq. cm, the sheath thickness is 0.152 cm and the diameter over the sheath is 2.28 cms. They are supported in equilateral formation with a distance between cable centres of 5.08 cms. Calculate the induced e.m.f. in each sheath when the cable is 2 km long and supply is 50 Hz. 5.08 cm 0.152 cm 2.28 cm Fig. E.9.7
Example 9.7: Three single core lead sheathed cables carry three-phase current of 400 A. The nominal conductor area of the cores is 1.25 sq. cm, the sheath thickness is 0.152 cm and the diameter over the sheath is 2.28 cms. They are supported in equilateral formation with a distance between cable centres of 5.08 cms. Calculate the induced e.m.f. in each sheath when the cable is 2 km long and supply is 50 Hz. 5.08 cm 0.152 cm 2.28 cm Fig. E.9.7
Power System Analysis and Design (MindTap Course List)
6th Edition
ISBN:9781305632134
Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Chapter4: Transmission Line Parameters
Section: Chapter Questions
Problem 4.22MCQ: In a three-phase line, in order to avoid unequal phase inductances due to unbalanced flux linkages,...
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Example 9.7: Three single core lead sheathed cables
carry three-phase current of 400 A . The nominal conductor
area of the cores is 1.25��.��, the sheath thickness is 0.152
cm and the diameter over the sheath is 2.28 cms . They are
supported in equilateral formation with a distance between
cable centres of 5.08 cms . Calculate the induced e.m.f. in each
sheath when the cable is 2 km long and supply is 50 Hz .
Fig. E.9.7

Transcribed Image Text:Example 9.7: Three single core lead sheathed cables
carry three-phase current of 400 A. The nominal conductor
area of the cores is 1.25 sq. cm, the sheath thickness is 0.152
cm and the diameter over the sheath is 2.28 cms. They are
supported in equilateral formation with a distance between
cable centres of 5.08 cms. Calculate the induced e.m.f. in each
sheath when the cable is 2 km long and supply is 50 Hz.
5.08 cm
0.152 cm
2.28 cm
Fig. E.9.7
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