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Solution bi 62 1/s ½ Vs 9. -a₂ Y(s) = X(s) ΣΡΟΚ Δ 199 Forward Paths P₁ = b Loops L = -91 S Y(s) b2 P₁₂ = bi P3- 52 S3 ; L3= 53 -92 52. X(s) PA, PA + P3D3 - { sum of Lep} + { two non touching Loops DK= Y(s) = X(S) 1- { sum of non-touching Loop. Gains by +b₂ (5, +b₁ (55)) (s² + αis² +α₂s + α3) /53 bs² + b₂s +b3 S³ +9₁s² + a₂s +93 Y(s) = X(s)

Solution bi 62 1/s ½ Vs 9. -a₂ Y(s) = X(s) ΣΡΟΚ Δ 199 Forward Paths P₁ = b Loops L = -91 S Y(s) b2 P₁₂ = bi P3- 52 S3 ; L3= 53 -92 52. X(s) PA, PA + P3D3 - { sum of Lep} + { two non touching Loops DK= Y(s) = X(S) 1- { sum of non-touching Loop. Gains by +b₂ (5, +b₁ (55)) (s² + αis² +α₂s + α3) /53 bs² + b₂s +b3 S³ +9₁s² + a₂s +93 Y(s) = X(s)

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Modern Control Engineering, Volume 4, Chapter 3. I would like to know the details of the method for the origin of the equation in the red circle. Thank you in advance for your answer.
Solution bi 62 1/s ½ Vs 9. -a₂ Y(s) = X(s) ΣΡΟΚ Δ 199 Forward Paths P₁ = b Loops L = -91 S Y(s) b2 P₁₂ = bi P3- 52 S3 ; L3= 53 -92 52. X(s) PA, PA + P3D3 - { sum of Lep} + { two non touching Loops DK= Y(s) = X(S) 1- { sum of non-touching Loop. Gains by +b₂ (5, +b₁ (55)) (s² + αis² +α₂s + α3) /53 bs² + b₂s +b3 S³ +9₁s² + a₂s +93 Y(s) = X(s)
Transcribed Image Text:Solution bi 62 1/s ½ Vs 9. -a₂ Y(s) = X(s) ΣΡΟΚ Δ 199 Forward Paths P₁ = b Loops L = -91 S Y(s) b2 P₁₂ = bi P3- 52 S3 ; L3= 53 -92 52. X(s) PA, PA + P3D3 - { sum of Lep} + { two non touching Loops DK= Y(s) = X(S) 1- { sum of non-touching Loop. Gains by +b₂ (5, +b₁ (55)) (s² + αis² +α₂s + α3) /53 bs² + b₂s +b3 S³ +9₁s² + a₂s +93 Y(s) = X(s)
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