Example 8.4 Find i(t) in the circuit of Fig. 8.10. Assume that the circuit has reached steady state att 0. Solution: For t < 0, the switch is closed. The capacitor acts like an open circuit while the inductor acts like a shunted circuit. The equivalent circuit is shown in Fig. 8.11(a). Thus, at t = 0, i(0) = 10 = 1 A, v(0) = 6i(0) = 6 V 4+ 6 1 = 0 42 42 ww 0.02 F v 9Ω 10 V 10 V 0.02 F=v 0.5 H 0.5 H Figure 8.10 For Example 8.4. (a) Figure 8.11 The circuit in Fig 8 10: (a) (b) ww m ww
Example 8.4 Find i(t) in the circuit of Fig. 8.10. Assume that the circuit has reached steady state att 0. Solution: For t < 0, the switch is closed. The capacitor acts like an open circuit while the inductor acts like a shunted circuit. The equivalent circuit is shown in Fig. 8.11(a). Thus, at t = 0, i(0) = 10 = 1 A, v(0) = 6i(0) = 6 V 4+ 6 1 = 0 42 42 ww 0.02 F v 9Ω 10 V 10 V 0.02 F=v 0.5 H 0.5 H Figure 8.10 For Example 8.4. (a) Figure 8.11 The circuit in Fig 8 10: (a) (b) ww m ww
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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![Example 8.4
Find i(t) in the circuit of Fig. 8.10. Assume that the circuit has reached
steady state att 0.
Solution:
For t < 0, the switch is closed. The capacitor acts like an open
while the inductor acts like a shunted circuit. The equivalent circuit is
shown in Fig. 8.11(a). Thus, at t = 0,
circuit
i(0) =
10
= 1 A,
v(0) = 6i(0) = 6 V
4 + 6
1= 0
42
www
42
ww
0.02 F v
9Ω
10 V
10 V
0.02 F=
0.5 H
0.5 H
Figure 8.10
For Example 8.4.
(a)
(b)
Figure 8.11
The circuit in Fig 8 10: (a) for t
ww mm
ww
ww-](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa30fa7f5-1afb-439e-946a-11a981bf4e41%2F208af119-7704-4687-86d4-f06819a321a7%2F0exee78_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Example 8.4
Find i(t) in the circuit of Fig. 8.10. Assume that the circuit has reached
steady state att 0.
Solution:
For t < 0, the switch is closed. The capacitor acts like an open
while the inductor acts like a shunted circuit. The equivalent circuit is
shown in Fig. 8.11(a). Thus, at t = 0,
circuit
i(0) =
10
= 1 A,
v(0) = 6i(0) = 6 V
4 + 6
1= 0
42
www
42
ww
0.02 F v
9Ω
10 V
10 V
0.02 F=
0.5 H
0.5 H
Figure 8.10
For Example 8.4.
(a)
(b)
Figure 8.11
The circuit in Fig 8 10: (a) for t
ww mm
ww
ww-
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