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EXAMPLE 8.11 The network of Fig. 8.34 was analyzed as Example 7.7, resulting in Vase = 0.35 V and In. = 7.6 mA. %3D a. Determine gm and compare to gmo- b. Find ra. c. Sketch the ac equivalent network for Fig. 8.34. d. Find Z. e. Calculate Z. f. Find A,. O 18 V

EXAMPLE 8.11 The network of Fig. 8.34 was analyzed as Example 7.7, resulting in Vase = 0.35 V and In. = 7.6 mA. %3D a. Determine gm and compare to gmo- b. Find ra. c. Sketch the ac equivalent network for Fig. 8.34. d. Find Z. e. Calculate Z. f. Find A,. O 18 V

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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EXAMPLE 8.11 The network of Fig. 8.34 was analyzed as Example 7.7, resulting in VGS. = 0.35 V and Ip, = 7.6 mA. a. Determine &m and compare to gmo- b. Find ra. c. Sketch the ac equivalent network for Fig. 8.34. d. Find Zi. e. Calculate Z,. f. Find A,. 9 18 V Rp 1.8 kO R1 110 M2 D Inss=6 mA =-3 V Re = 10 pS C1 G Z, = Cs 10 MQ Ry 1502 R2 Page 51 of 117 ENGG_EEE_LECTURE NOTES_03Feb2022_V1.2
Transcribed Image Text:EXAMPLE 8.11 The network of Fig. 8.34 was analyzed as Example 7.7, resulting in VGS. = 0.35 V and Ip, = 7.6 mA. a. Determine &m and compare to gmo- b. Find ra. c. Sketch the ac equivalent network for Fig. 8.34. d. Find Zi. e. Calculate Z,. f. Find A,. 9 18 V Rp 1.8 kO R1 110 M2 D Inss=6 mA =-3 V Re = 10 pS C1 G Z, = Cs 10 MQ Ry 1502 R2 Page 51 of 117 ENGG_EEE_LECTURE NOTES_03Feb2022_V1.2
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