Example 7.10. a. Design a bandpass FIR filter with the following specifications: Lower stopband 0-500 Hz Passband = 1,600-2,300 Hz Upper stopband= 3,500-4,000 Hz Stopband attenuation 50 dB Passband ripple = 0.05 dB Sampling rate = 8,000 Hz
Example 7.10. a. Design a bandpass FIR filter with the following specifications: Lower stopband 0-500 Hz Passband = 1,600-2,300 Hz Upper stopband= 3,500-4,000 Hz Stopband attenuation 50 dB Passband ripple = 0.05 dB Sampling rate = 8,000 Hz
Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
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Transcribed Image Text:Example 7.10.
a. Design a bandpass FIR filter with the following specifications:
Lower stopband 0-500 Hz
Passband = 1,600-2,300 Hz
Upper stopband = 3,500 4,000 Hz
Stopband attenuation = 50 dB
Passband ripple = 0.05 dB
Sampling rate = 8,000 Hz
Solution:
a. A₁=1600-5001/8000= 0.1375 and 4/2= 13500-23001/8000= 0.15
N₁3.3/0.1375= 24 and N₂ = 3.3/0.15 = 22
/1
-/۲
Choosing N=25 filter coefficients using the Hamming window
method:
fi= (1600+500)/2= 1050 Hz and 2 = (3500+2300)/2=2900 Hz.
The normalized lower and upper cutoff frequencies are calculated as:
1050 x 2#
NL=
SH=
N = 33/0₁ =
N₂= 33/0₂
Sucr
8000
2900 x 2T
8000
AG: 27fci
14
zoter.
fu
= 0.2625# radians and
2
= 0.725# radians,
N₂ 29 odd, tue
24
22
0.26k ved
= 0.729 red
hen
h(2)
h(3)
W14)
W(0)
WIT
W/2)
h(0)
Hamm
رحلنا
-
- (-1)
h(-2)
(-3)
-1²-17
S
W(
-1
-3
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