Example 7-3: The reverse current in a certain 12 V, 2.4 W zener diode must be at least 5 mA to ensure that the diode remains in breakdown. The diode is to be used in the regulator circuit shown in Fig 7-9, where Vi can vary from 18 V to 24 V. Find a suitable value for RS and the minimur power dissipation that RS should have. rated Solution: Rs IZK = 5 mA & IZM= Pz/Vz=2.4/12 = 200 mA %3D Vz R2600 (when the switch S is open) = 0 & = 00

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Example 7-3:
The reverse current in a certain 12 V, 2.4 W zener diode must be at least 5 mA to ensure that
the diode remains in breakdown. The diode is to be used in the regulator circuit shown in Fig.
7-9, where Vi can vary from 18 V to 24 V. Find a suitable value for RS and the minimum
rated power dissipation that RS should have.
Rs
Solution:
IZK = 5 mA & IZM= Pz/Vz=2.4/12 = 200 mA
V-
Vz
R26002
(when the switch S is open)
= 00
Transcribed Image Text:Example 7-3: The reverse current in a certain 12 V, 2.4 W zener diode must be at least 5 mA to ensure that the diode remains in breakdown. The diode is to be used in the regulator circuit shown in Fig. 7-9, where Vi can vary from 18 V to 24 V. Find a suitable value for RS and the minimum rated power dissipation that RS should have. Rs Solution: IZK = 5 mA & IZM= Pz/Vz=2.4/12 = 200 mA V- Vz R26002 (when the switch S is open) = 00
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