Example 7-3: The reverse current in a certain 12 V, 2.4 W zener diode must be at least 5 mA to ensure that the diode remains in breakdown. The diode is to be used in the regulator circuit shown in Fig 7-9, where Vi can vary from 18 V to 24 V. Find a suitable value for RS and the minimur power dissipation that RS should have. rated Solution: Rs IZK = 5 mA & IZM= Pz/Vz=2.4/12 = 200 mA %3D Vz R2600 (when the switch S is open) = 0 & = 00
Example 7-3: The reverse current in a certain 12 V, 2.4 W zener diode must be at least 5 mA to ensure that the diode remains in breakdown. The diode is to be used in the regulator circuit shown in Fig 7-9, where Vi can vary from 18 V to 24 V. Find a suitable value for RS and the minimur power dissipation that RS should have. rated Solution: Rs IZK = 5 mA & IZM= Pz/Vz=2.4/12 = 200 mA %3D Vz R2600 (when the switch S is open) = 0 & = 00
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Question
![Example 7-3:
The reverse current in a certain 12 V, 2.4 W zener diode must be at least 5 mA to ensure that
the diode remains in breakdown. The diode is to be used in the regulator circuit shown in Fig.
7-9, where Vi can vary from 18 V to 24 V. Find a suitable value for RS and the minimum
rated power dissipation that RS should have.
Rs
Solution:
IZK = 5 mA & IZM= Pz/Vz=2.4/12 = 200 mA
V-
Vz
R26002
(when the switch S is open)
= 00](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fac51ea08-d7ca-444b-afe1-a4464c4fe1e7%2F4c7d67c4-b4f9-4510-83b5-f0a72a92eddc%2Fx2zsl6f_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Example 7-3:
The reverse current in a certain 12 V, 2.4 W zener diode must be at least 5 mA to ensure that
the diode remains in breakdown. The diode is to be used in the regulator circuit shown in Fig.
7-9, where Vi can vary from 18 V to 24 V. Find a suitable value for RS and the minimum
rated power dissipation that RS should have.
Rs
Solution:
IZK = 5 mA & IZM= Pz/Vz=2.4/12 = 200 mA
V-
Vz
R26002
(when the switch S is open)
= 00
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