EXAMPLE 6 We can use Gaussian elimination to find a right inverse of an m xn matrix A, so long as the rank of A is equal to m. The fact that we have free variables when m < n will give many choices of right inverse. For example, taking 1. A = -1 2 -1 we apply Gaussian elimination to the augmented matrix 1 -1 1 1 -1 1 1 0. 2 -1 0. 0. 0. 1 -2 -2 1 0- 1 -1 1 -2 -2 []- From this we see that the general solution of Ax = is -1 X = +s is and the general solution of Ax = X = + If we take s =t = 0, we get the right inverse |-1 B = -2 1 0. 0.
EXAMPLE 6 We can use Gaussian elimination to find a right inverse of an m xn matrix A, so long as the rank of A is equal to m. The fact that we have free variables when m < n will give many choices of right inverse. For example, taking 1. A = -1 2 -1 we apply Gaussian elimination to the augmented matrix 1 -1 1 1 -1 1 1 0. 2 -1 0. 0. 0. 1 -2 -2 1 0- 1 -1 1 -2 -2 []- From this we see that the general solution of Ax = is -1 X = +s is and the general solution of Ax = X = + If we take s =t = 0, we get the right inverse |-1 B = -2 1 0. 0.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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I really cannot see how this problem is going from the reduced matrix (via Gaussian elimination) to the general solution. Can anyone please explain the steps to arrive to the general solution and then give another right inverse of matrix A.
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