Use a graphing utility to find the inverse, if it exists, of the given matrix. Matrix: \[ \begin{bmatrix} 25 & 57 & -17 \\ 21 & -2 & 8 \\ -9 & -40 & 27 \end{bmatrix} \] Select the correct choice below and, if necessary, fill in the answer box within your choice. - A. The inverse of the matrix \[ \begin{bmatrix} 25 & 57 & -17 \\ 21 & -2 & 8 \\ -9 & -40 & 27 \end{bmatrix} \] is [ ]. (Type an integer or decimal for each matrix element. Round to two decimal places as needed.) - B. The matrix has no inverse. Use the given inverse of the coefficient matrix to solve the following system of equations. \[ \begin{align*} 25x + 62y - 12z &= 10 \\ 18x - 12y + 7z &= -9 \\ 5x + 6y - z &= 13 \\ \end{align*} \] The inverse matrix provided is: \[ \begin{bmatrix} -0.06 & -0.02 & 0.56 \\ 0.10 & 0.07 & -0.75 \\ 0.32 & 0.31 & -2.72 \\ \end{bmatrix} \] The solution is \(x = \_\_\), \(y = \_\_\), and \(z = \_\_\). *(Round to two decimal places as needed.)*
Use a graphing utility to find the inverse, if it exists, of the given matrix. Matrix: \[ \begin{bmatrix} 25 & 57 & -17 \\ 21 & -2 & 8 \\ -9 & -40 & 27 \end{bmatrix} \] Select the correct choice below and, if necessary, fill in the answer box within your choice. - A. The inverse of the matrix \[ \begin{bmatrix} 25 & 57 & -17 \\ 21 & -2 & 8 \\ -9 & -40 & 27 \end{bmatrix} \] is [ ]. (Type an integer or decimal for each matrix element. Round to two decimal places as needed.) - B. The matrix has no inverse. Use the given inverse of the coefficient matrix to solve the following system of equations. \[ \begin{align*} 25x + 62y - 12z &= 10 \\ 18x - 12y + 7z &= -9 \\ 5x + 6y - z &= 13 \\ \end{align*} \] The inverse matrix provided is: \[ \begin{bmatrix} -0.06 & -0.02 & 0.56 \\ 0.10 & 0.07 & -0.75 \\ 0.32 & 0.31 & -2.72 \\ \end{bmatrix} \] The solution is \(x = \_\_\), \(y = \_\_\), and \(z = \_\_\). *(Round to two decimal places as needed.)*
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Please help me to solve the problem on the screenshots.
![Use a graphing utility to find the inverse, if it exists, of the given matrix.
Matrix:
\[
\begin{bmatrix}
25 & 57 & -17 \\
21 & -2 & 8 \\
-9 & -40 & 27
\end{bmatrix}
\]
Select the correct choice below and, if necessary, fill in the answer box within your choice.
- A. The inverse of the matrix
\[
\begin{bmatrix}
25 & 57 & -17 \\
21 & -2 & 8 \\
-9 & -40 & 27
\end{bmatrix}
\]
is [ ].
(Type an integer or decimal for each matrix element. Round to two decimal places as needed.)
- B. The matrix has no inverse.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F00da0c39-9702-4663-a1e7-00293d43ce13%2Ff635afd4-63fd-4f08-bd43-967f929991c3%2Fe9k09uh_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Use a graphing utility to find the inverse, if it exists, of the given matrix.
Matrix:
\[
\begin{bmatrix}
25 & 57 & -17 \\
21 & -2 & 8 \\
-9 & -40 & 27
\end{bmatrix}
\]
Select the correct choice below and, if necessary, fill in the answer box within your choice.
- A. The inverse of the matrix
\[
\begin{bmatrix}
25 & 57 & -17 \\
21 & -2 & 8 \\
-9 & -40 & 27
\end{bmatrix}
\]
is [ ].
(Type an integer or decimal for each matrix element. Round to two decimal places as needed.)
- B. The matrix has no inverse.
![Use the given inverse of the coefficient matrix to solve the following system of equations.
\[
\begin{align*}
25x + 62y - 12z &= 10 \\
18x - 12y + 7z &= -9 \\
5x + 6y - z &= 13 \\
\end{align*}
\]
The inverse matrix provided is:
\[
\begin{bmatrix}
-0.06 & -0.02 & 0.56 \\
0.10 & 0.07 & -0.75 \\
0.32 & 0.31 & -2.72 \\
\end{bmatrix}
\]
The solution is \(x = \_\_\), \(y = \_\_\), and \(z = \_\_\).
*(Round to two decimal places as needed.)*](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F00da0c39-9702-4663-a1e7-00293d43ce13%2Ff635afd4-63fd-4f08-bd43-967f929991c3%2Fi3dd25j_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Use the given inverse of the coefficient matrix to solve the following system of equations.
\[
\begin{align*}
25x + 62y - 12z &= 10 \\
18x - 12y + 7z &= -9 \\
5x + 6y - z &= 13 \\
\end{align*}
\]
The inverse matrix provided is:
\[
\begin{bmatrix}
-0.06 & -0.02 & 0.56 \\
0.10 & 0.07 & -0.75 \\
0.32 & 0.31 & -2.72 \\
\end{bmatrix}
\]
The solution is \(x = \_\_\), \(y = \_\_\), and \(z = \_\_\).
*(Round to two decimal places as needed.)*
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