Example 5: The following information is given for a 300-kW, 600-V, long-shunt compound generator : Shunt field resistance = 75 Q, armature resistance including brush resistance = 0.03 0, commutating field winding resistance 0.011 2, series field resistance = 0.012 N, divertor resistance 0.036 Q. When the machine is delivering full |load, calculate the voltage and power generated by the armature. Solution: Power output = 300,000 W Output current = 300,000/600 = 500 A Ish = 600/75 = 8 A 8 A 500 A 1. 0.012 2 I, = 500 + 8 = 508 A Since the series field resistance and divertor 600 V 0.011 2 resistance are in parallel their combined resistance 0.012x 0.036 is = 0.012+0.036 Total armature circuit resistance = 0.03 + 0.011 + 0.009 = 0.05 2 Voltage drop 508x0.05 = 25.4 V Voltage generated by armature = 600 + 25.4 625.4 V 0.009 2 0.03 2 Power generated = 625.4x508 = 317,700 = 317.7 kw using matlab E00 U SL

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