EXAMPLE 5 Find an equation of the tangent line to the parabola y = x2 - 4x + 6 at the point (1, 3). SOLUTION From the previous example, we know the derivative of f(x) = x2 – 4x + 6 at the number a is f'(a) = 2a - 4. Therefore the slope of the tangent line at (1, 3) is f'(1) = 2(1) – 4 = Thus an equation of the tangent line, shown in the figure, is y - (0)-O(--O) or y =

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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EXAMPLE 5
Find an equation of the tangent line to the parabola
y = x2 - 4x + 6 at the point (1, 3).
SOLUTION From the previous example, we know the derivative of
f(x) = x2 – 4x + 6 at the number a is f'(a) = 2a - 4. Therefore the slope of
Thus an equation of
the tangent line at (1, 3) is f'(1) = 2(1) – 4 =
the tangent line, shown in the figure, is
y-(0)-O(--O)
X -
or
y =
Transcribed Image Text:EXAMPLE 5 Find an equation of the tangent line to the parabola y = x2 - 4x + 6 at the point (1, 3). SOLUTION From the previous example, we know the derivative of f(x) = x2 – 4x + 6 at the number a is f'(a) = 2a - 4. Therefore the slope of Thus an equation of the tangent line at (1, 3) is f'(1) = 2(1) – 4 = the tangent line, shown in the figure, is y-(0)-O(--O) X - or y =
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