Solve the related problem. EXAMPLE 5-10Calculate the Q-point values (Ic and VCE) for the circuit in Figure 5–23.FIGURE 5-23Vcc+10 VRe10 ΚΩRB180 kOBDc = 1000.7 VSolution Using Equation 5–13, the collector current is10 V – 0.7 VVcc - VBEIc =Rc + RB/BpC=788 μΑ10 kΩ + 180 kΩ/100Using Equation 5–14, the collector-to-emitter voltage isVCE = Vcc - IcRc = 10 V – (788 µA)(10 kN) = 2.12 VRelated ProblemCalculate the Q-point values in Figure 5-23 for Bpc = 200 and determine the percentchange in the Q-point from Bpc = 100 to BDc = 200.

We will apply KVL in input loop and output loop to get Q-point. Applying KVL in input loop we get:…

EXAMPLE 5-10 Calculate the Q-point values (Ic and VCE) for the circuit in Figure 5-23. FIGURE 5-23 Vcc +10 V RC 10 KΩ RB 180 kl Boc = 100 0.7 V Solution Using Equation 5-13, the collector current is Vcc - VBE Ic RC+ RB/ βpο 10 kΩ+ 180 kΩ/100 10 V – 0.7 V - 788 μΑ Using Equation 5-14, the collector-to-emitter voltage is VCE = Vcc - IcRc = 10 V - (788 µA)(10 kN) = 2.12 V Related Problem = 200 and determine the percent Calculate the Q-point values in Figure 5-23 for BDC change in the Q-point from Bpc 100 to BDC 200. %3D

EXAMPLE 5-10 Calculate the Q-point values (Ic and VCE) for the circuit in Figure 5-23. FIGURE 5-23 Vcc +10 V RC 10 KΩ RB 180 kl Boc = 100 0.7 V Solution Using Equation 5-13, the collector current is Vcc - VBE Ic RC+ RB/ βpο 10 kΩ+ 180 kΩ/100 10 V – 0.7 V - 788 μΑ Using Equation 5-14, the collector-to-emitter voltage is VCE = Vcc - IcRc = 10 V - (788 µA)(10 kN) = 2.12 V Related Problem = 200 and determine the percent Calculate the Q-point values in Figure 5-23 for BDC change in the Q-point from Bpc 100 to BDC 200. %3D

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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