This is the problem: Consider the Boolean expression (X+Y)(+Z)(Y+Z). Obtain the sum-of-products. Use a K-map to obtain its minimal sum-of-products. The image below is how far I got. Every K-Map exercise I've done so far has always had minterms with the same number of variables, but I came up with this SOP that has 2 and 3 variable minterms; so I don't know if I did something wrong in obtaining the SOP or how I'm supposed to enter the minterms in the K-Map here.
This is the problem: Consider the Boolean expression (X+Y)(+Z)(Y+Z). Obtain the sum-of-products. Use a K-map to obtain its minimal sum-of-products. The image below is how far I got. Every K-Map exercise I've done so far has always had minterms with the same number of variables, but I came up with this SOP that has 2 and 3 variable minterms; so I don't know if I did something wrong in obtaining the SOP or how I'm supposed to enter the minterms in the K-Map here.
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
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This is the problem:
Consider the Boolean expression (X+Y)(+Z)(Y+Z).
-
- Obtain the sum-of-products.
- Use a K-map to obtain its minimal sum-of-products.
The image below is how far I got. Every K-Map exercise I've done so far has always had minterms with the same number of variables, but I came up with this SOP that has 2 and 3 variable minterms; so I don't know if I did something wrong in obtaining the SOP or how I'm supposed to enter the minterms in the K-Map here.
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Transcribed Image Text:1) a.
(X+Y)(X + Z) (Y + Z)
=
(XX + XZ + YX + YZ)(Y + Z)
=
(XXY + XXZ + XZY + XZZ + YXY + YXZ + YZY + YZZ)
= (OY + OZ + XYZ + XZ + YX + YXZ + YZ + YZ)
(XYZ + XZ + XY + XYZ + YZ)
=
X
X
YZ ÝZ YZ YZ
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