Exampleweighing 450 N is lowered into a tank containinga two-fluid layer of water and mercury. Determinethe position of block at mercury-water interfacewhen it has reached equilibrium.A metallic cube 30 cm side andWater30 cmh,CubeThe metallic cubeSolution. Refer to Figsinks beneath the water surface and comes to restMercuryat the water-mercury interface.As per principle of floatation, we have weight

Given Weight of cube=450N Length of cube=30cm

Example 4. A metallic cube 30 cm side and weighing 450N is lowered into a tank containing a two-fluid layer of water and mercury. Determine the position of block at mercury-water interface when it has reached equilibrium.

Example 4. A metallic cube 30 cm side and weighing 450N is lowered into a tank containing a two-fluid layer of water and mercury. Determine the position of block at mercury-water interface when it has reached equilibrium.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Question

Example
weighing 450 N is lowered into a tank containing
a two-fluid layer of water and mercury. Determine
the position of block at mercury-water interface
when it has reached equilibrium.
A metallic cube 30 cm side and
Water
30 cm
h,
Cube
The metallic cube
Solution. Refer to Fig
sinks beneath the water surface and comes to rest
Mercury
at the water-mercury interface.
As per principle of floatation, we have weight

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