EXAMPLE 3. A 25-kw three-phase oonverter has a d-o output voltage of 230 volta. Asuming negligible loeses and unity power factor, caloulate: (@) the ae input voltage between rings; (b) the full-load d-a output; (e) the full-load a-e input per line. Solution ' (a) E. - 0.612 x 230 = 141 volta %3D P 25,000 230 I. - 106.7 amp I. - 0.943 X 108.7 - 102.3 amp EAMPLI 4. A 1,500-kw six-phase synchronous converter has a full- lond d-e valtage of 600. Determine: (a) the ao voltage between rings; (4) the d-o output; (c) the a-o input per line. Solution (a) B. - 0.354 X 600 - 212.4 volta P 1,500,000 600 2,500 amp (6) (e) I.- 0.472 X 2,500 - 1,180 amp EXAMPLE 5. A 5,000-kw 1,200-volt 12-phase synohronous converter operates at full load at an efficiency of 96 per oent and a power factor of 0.95. Calculate: (a) the a-c voltage between rings; (b) the d-c output; (c) the alternating current in each of the 12 wires. Solution (a) E. - 0.182 × 1,200 - 218.4 volta 5,000,000 1,200 (6) la - 4,167 amp (c) I. (efficiency - 100 per cent and power factor 1) 0.236 X 4,167 - 984 amp In (efficiency = 96 per cent and power factor - 0.95) 984 0,96 X 0.95 - 1,080 amp
EXAMPLE 3. A 25-kw three-phase oonverter has a d-o output voltage of 230 volta. Asuming negligible loeses and unity power factor, caloulate: (@) the ae input voltage between rings; (b) the full-load d-a output; (e) the full-load a-e input per line. Solution ' (a) E. - 0.612 x 230 = 141 volta %3D P 25,000 230 I. - 106.7 amp I. - 0.943 X 108.7 - 102.3 amp EAMPLI 4. A 1,500-kw six-phase synchronous converter has a full- lond d-e valtage of 600. Determine: (a) the ao voltage between rings; (4) the d-o output; (c) the a-o input per line. Solution (a) B. - 0.354 X 600 - 212.4 volta P 1,500,000 600 2,500 amp (6) (e) I.- 0.472 X 2,500 - 1,180 amp EXAMPLE 5. A 5,000-kw 1,200-volt 12-phase synohronous converter operates at full load at an efficiency of 96 per oent and a power factor of 0.95. Calculate: (a) the a-c voltage between rings; (b) the d-c output; (c) the alternating current in each of the 12 wires. Solution (a) E. - 0.182 × 1,200 - 218.4 volta 5,000,000 1,200 (6) la - 4,167 amp (c) I. (efficiency - 100 per cent and power factor 1) 0.236 X 4,167 - 984 amp In (efficiency = 96 per cent and power factor - 0.95) 984 0,96 X 0.95 - 1,080 amp
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
Related questions
Question
How did they compute these encircled value, formula is enough, I just need to know it. Thanks! Please include symbol and units. Thanks!
Transcribed Image Text:EXAMPLE 3. A 25-kw three-phase oonverter has a d-o output voltage of
230 volta. Assuming negligible loeses and unity power factor, caloulate:
(a) the ae input voltage between rings; (b) the full-load d-a output;
(e) the full-load ae input per line.
Solution
E. - 0.612 x 230 141 volta
P 25,000
230
I, - 0.943 X 108.7 - 102.3 amp
(a)
In
108.7 amp
(e)
BAMPLI 4. A 1,500-kw six-phase synchronous converter has a full-
load d-e voltage of 600. Determine: (a) the a-o voltago between rings;
(®) the d-o output; (c) the a-o input per line.
Solution
E. = 0.354 X 600 = 212.4 volta
1,500,000
Bu
600
(6)
I. =
2,500 amp
(c)
I- 0.472 X 2,500 = 1,180 amp
EXAMPLE 5. A 5,000-kw 1,200-volt 12-phase synohronous converter
operates at full load at an efficiency of 96 per oent and a power factor of
0.95. Calculate: (a) the a-c voltage between rings; (b) the d-e output;
(e) \the alternating current in each of the 12 wires.
Solution
(a) E. - 0.182 x 1,200 - 218.4 volta
5,000,000
1,200
(6) Ia -
4,167 amp
(c) I. (efficiency = 100 per cent and power factor = 1)
0.236 × 4,167 - 984 amp
In (efficiency = 96 per cent and power factor - 0.95)
984
0.96 X 0.95
- 1,080 amp
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 3 steps
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, electrical-engineering and related others by exploring similar questions and additional content below.Recommended textbooks for you
Introductory Circuit Analysis (13th Edition)
Electrical Engineering
ISBN:
9780133923605
Author:
Robert L. Boylestad
Publisher:
PEARSON
Delmar's Standard Textbook Of Electricity
Electrical Engineering
ISBN:
9781337900348
Author:
Stephen L. Herman
Publisher:
Cengage Learning
Programmable Logic Controllers
Electrical Engineering
ISBN:
9780073373843
Author:
Frank D. Petruzella
Publisher:
McGraw-Hill Education
Introductory Circuit Analysis (13th Edition)
Electrical Engineering
ISBN:
9780133923605
Author:
Robert L. Boylestad
Publisher:
PEARSON
Delmar's Standard Textbook Of Electricity
Electrical Engineering
ISBN:
9781337900348
Author:
Stephen L. Herman
Publisher:
Cengage Learning
Programmable Logic Controllers
Electrical Engineering
ISBN:
9780073373843
Author:
Frank D. Petruzella
Publisher:
McGraw-Hill Education
Fundamentals of Electric Circuits
Electrical Engineering
ISBN:
9780078028229
Author:
Charles K Alexander, Matthew Sadiku
Publisher:
McGraw-Hill Education
Electric Circuits. (11th Edition)
Electrical Engineering
ISBN:
9780134746968
Author:
James W. Nilsson, Susan Riedel
Publisher:
PEARSON
Engineering Electromagnetics
Electrical Engineering
ISBN:
9780078028151
Author:
Hayt, William H. (william Hart), Jr, BUCK, John A.
Publisher:
Mcgraw-hill Education,