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EXAMPLE 3. A 25-kw three-phase oonverter has a d-o output voltage of 230 volta. Asuming negligible loeses and unity power factor, caloulate: (@) the ae input voltage between rings; (b) the full-load d-a output; (e) the full-load a-e input per line. Solution ' (a) E. - 0.612 x 230 = 141 volta %3D P 25,000 230 I. - 106.7 amp I. - 0.943 X 108.7 - 102.3 amp EAMPLI 4. A 1,500-kw six-phase synchronous converter has a full- lond d-e valtage of 600. Determine: (a) the ao voltage between rings; (4) the d-o output; (c) the a-o input per line. Solution (a) B. - 0.354 X 600 - 212.4 volta P 1,500,000 600 2,500 amp (6) (e) I.- 0.472 X 2,500 - 1,180 amp EXAMPLE 5. A 5,000-kw 1,200-volt 12-phase synohronous converter operates at full load at an efficiency of 96 per oent and a power factor of 0.95. Calculate: (a) the a-c voltage between rings; (b) the d-c output; (c) the alternating current in each of the 12 wires. Solution (a) E. - 0.182 × 1,200 - 218.4 volta 5,000,000 1,200 (6) la - 4,167 amp (c) I. (efficiency - 100 per cent and power factor 1) 0.236 X 4,167 - 984 amp In (efficiency = 96 per cent and power factor - 0.95) 984 0,96 X 0.95 - 1,080 amp

EXAMPLE 3. A 25-kw three-phase oonverter has a d-o output voltage of 230 volta. Asuming negligible loeses and unity power factor, caloulate: (@) the ae input voltage between rings; (b) the full-load d-a output; (e) the full-load a-e input per line. Solution ' (a) E. - 0.612 x 230 = 141 volta %3D P 25,000 230 I. - 106.7 amp I. - 0.943 X 108.7 - 102.3 amp EAMPLI 4. A 1,500-kw six-phase synchronous converter has a full- lond d-e valtage of 600. Determine: (a) the ao voltage between rings; (4) the d-o output; (c) the a-o input per line. Solution (a) B. - 0.354 X 600 - 212.4 volta P 1,500,000 600 2,500 amp (6) (e) I.- 0.472 X 2,500 - 1,180 amp EXAMPLE 5. A 5,000-kw 1,200-volt 12-phase synohronous converter operates at full load at an efficiency of 96 per oent and a power factor of 0.95. Calculate: (a) the a-c voltage between rings; (b) the d-c output; (c) the alternating current in each of the 12 wires. Solution (a) E. - 0.182 × 1,200 - 218.4 volta 5,000,000 1,200 (6) la - 4,167 amp (c) I. (efficiency - 100 per cent and power factor 1) 0.236 X 4,167 - 984 amp In (efficiency = 96 per cent and power factor - 0.95) 984 0,96 X 0.95 - 1,080 amp

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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How did they compute these encircled value, formula is enough, I just need to know it. Thanks! Please include symbol and units. Thanks!

EXAMPLE 3. A 25-kw three-phase oonverter has a d-o output voltage of 230 volta. Assuming negligible loeses and unity power factor, caloulate: (a) the ae input voltage between rings; (b) the full-load d-a output; (e) the full-load ae input per line. Solution E. - 0.612 x 230 141 volta P 25,000 230 I, - 0.943 X 108.7 - 102.3 amp (a) In 108.7 amp (e) BAMPLI 4. A 1,500-kw six-phase synchronous converter has a full- load d-e voltage of 600. Determine: (a) the a-o voltago between rings; (®) the d-o output; (c) the a-o input per line. Solution E. = 0.354 X 600 = 212.4 volta 1,500,000 Bu 600 (6) I. = 2,500 amp (c) I- 0.472 X 2,500 = 1,180 amp EXAMPLE 5. A 5,000-kw 1,200-volt 12-phase synohronous converter operates at full load at an efficiency of 96 per oent and a power factor of 0.95. Calculate: (a) the a-c voltage between rings; (b) the d-e output; (e) \the alternating current in each of the 12 wires. Solution (a) E. - 0.182 x 1,200 - 218.4 volta 5,000,000 1,200 (6) Ia - 4,167 amp (c) I. (efficiency = 100 per cent and power factor = 1) 0.236 × 4,167 - 984 amp In (efficiency = 96 per cent and power factor - 0.95) 984 0.96 X 0.95 - 1,080 amp
Transcribed Image Text:EXAMPLE 3. A 25-kw three-phase oonverter has a d-o output voltage of 230 volta. Assuming negligible loeses and unity power factor, caloulate: (a) the ae input voltage between rings; (b) the full-load d-a output; (e) the full-load ae input per line. Solution E. - 0.612 x 230 141 volta P 25,000 230 I, - 0.943 X 108.7 - 102.3 amp (a) In 108.7 amp (e) BAMPLI 4. A 1,500-kw six-phase synchronous converter has a full- load d-e voltage of 600. Determine: (a) the a-o voltago between rings; (®) the d-o output; (c) the a-o input per line. Solution E. = 0.354 X 600 = 212.4 volta 1,500,000 Bu 600 (6) I. = 2,500 amp (c) I- 0.472 X 2,500 = 1,180 amp EXAMPLE 5. A 5,000-kw 1,200-volt 12-phase synohronous converter operates at full load at an efficiency of 96 per oent and a power factor of 0.95. Calculate: (a) the a-c voltage between rings; (b) the d-e output; (e) \the alternating current in each of the 12 wires. Solution (a) E. - 0.182 x 1,200 - 218.4 volta 5,000,000 1,200 (6) Ia - 4,167 amp (c) I. (efficiency = 100 per cent and power factor = 1) 0.236 × 4,167 - 984 amp In (efficiency = 96 per cent and power factor - 0.95) 984 0.96 X 0.95 - 1,080 amp
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