Consolid Example 3test ChyThe equation of effective stress failure envelope fornormally consolidated clayey soil is03000Tf = o'tan 27A drained triaxial test was conducted with the same soil atthe chamber confining pressure of 100 kN/m². Calculatethe deviator stress at failure (Answer: 166.3 kN/m²)

Answered: Image /qna-images/answer/818c5817-901e-4c65-970e-6061a880a3b6.jpg

Example 3 The equation of effective stress failure envelope for normally consolidated clayey soil is 107 lloaroo Tf = o'tan 27 A drained triaxial test was conducted with the same soil at the chamber confining pressure of 100 kN/m². Calculate the deviator stress at failure (Answer: 166.3 kN/m²) 03 (

Example 3 The equation of effective stress failure envelope for normally consolidated clayey soil is 107 lloaroo Tf = o'tan 27 A drained triaxial test was conducted with the same soil at the chamber confining pressure of 100 kN/m². Calculate the deviator stress at failure (Answer: 166.3 kN/m²) 03 (

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

5. A consolidated, undrained triaxial test is being carried out on a normally consolidated clay where c - 0 and p'= 26'. The triaxial specimen was consolidated under a cell pressure of 300 kPa and backpressure of 80 kPa. Skempton's A parameter at failure is estimated to be 0.80. The drainage valve has since been dosed and the vertical deviator stress increased to failure. What would be the deviator stress and pore water pressure at failure?
6. ( A silty sand sample failed during a consolidated-undrained triaxial test at o,=280 kPa and 0,=170 kPa. With the assumption that c=0 and A=0.65, determine the consolidated-undrained friction angle de and a drained friction angle o. If a consolidated-undrained test on such a soil is conducted at a confining pressure o,=340 kPa, what will be major total and effective stresses and the pore water pressure at failure? What will be the maximum shear stress t during a "slow" direct shear test, if the vertical stress o,=160 kPa? cu - 141° $' = 21.0° %3D 560 kpQ 417 197 RPa T = G1.4 RPa
A consolidated-undrained tri-axial test was conducted on a normally consolidated clay sample and the results are as follows: Chamber confining pressure = 115 kPa, Deviator stress at failure = 81 kPa, Pore Water Pressure = 62 kPa. These results were used to determine the drained friction angle of the soil. Compute the deviator stress (kPa) at failure when the drained test was conducted with the chamber confining pressure changed to 159 kPa. Round off to two decimal places.
A) The results of two consolidated-drained triaxial tests on clay are given below in Table 2. Table 2: Results of CDT tests. Specimen Chamber Pressure I II 3, kPa 110 220 Deviator Stress 01-03, kPa 220 400 a) Calculate the shear strength parameters of the soil. b) What are the normal and shear stresses on a plane inclined at 38° to the major principal plane for Specimen I? c) What are the normal and shear stresses on the failure plane at failure for Specimen II? B) The laboratory test results of a standard Proctor test are given in the following table.
: In a tri-axial test of a silty soil, the sample failed at normal stress of 475 kPa and a shear stress of 350 kPa. Which of the following gives the angle of internal friction? Compute the angle that the failure plane makes with the x-axis. Compute the maximum failure stress.
A sample of pure Clay, (C) soil with two specimens underwent an unconsolidated undrained test with a cell pressure of 50 kN/m2 and 100 kN/m2. The test is under short term analysis test. The results are as followings. From the result below, what is the shear strength of the soil? Cell pressure, kN/m² 50 100 Max Maximum deviator stress, kN/m² 120 170
7.12 A sand specimen was subjected to a drained shear test using hollow cylin- der test equipment. Failure was caused by increasing the inside pressure while keeping the outside pressure constant. At failure, o, = 193 kN/m² and o; = 264 kN/m². The inside and outside radii of the specimen were 40 and 60 mm, respectively. (a) Calculate the soil friction angle. (b) Calculate the axial stress on the specimen at failure.
A specimen of clean sand when subjected to direct shear test failed at stress of 1.20 kg/cm2 when normal stress was 1.60 kg/cm2. Determine: Angle of internal friction. Deviator stress at which the failure will take place if a cylindrical sample of the same sand is subjected to tri-axial test with a cell pressure of 1 kg/cm2.
1. A specimen of sandy silt, when subjected to a drained triaxial test failed at major and minor principal stress of 1.20 kg/cm2 and 0.5 kg/cm2 respectively. At what value of deviator stress would another sample of the same soil fail, if it were subjected to an all-around pressure of 0.75 kg/cm2? a. 2.01 kg/cm2 b.2.34 kg/cm2 c. 1.89 kg/cm2 d. 1.05 kg/cm2
Question 42 The results of two consolidated-drained test triaxial tests on a clay are given below: Specimen No. Chamber Pressure Deviator Stress 105 220 210 400 1. Determine the angle of internal friction. 2. Determine the cohesion of the clay. 3. Determine the normal stress on the point on the failure plane of the 2nd specimen. Question 1: A. 26.744 O Question 1: B. 26.042 Question 1: C. 27.871 O Question 1: D. 27.486 Question 2: A. 10.737 O Question 2: B. 12.141 Question 2: C. 17.372 Question 2: D. 14.836 Question 3: A. 317.694 O Question 3: B. 232.575 Question 3: C. 230.306 O Question 3: D. 322.194
Example 9.2: A clay soil, tested in a consolidometer, showed a decrease in void res •m 1.20 to 1.10 when the presure was increased from 0.25 to 0.50 kgflem?. Calculate to. efficient of compressibility (a) and the coefficient of volume compressibility (m). If t •ficient of consolidation (c,) determined in the test for the given stress increment u m?/year, calculate the coefficient of permeability in cm/s. If the sample tested at the site was taken from a clay layer 3.0 m in thickness, determin consolidation settlement resulting from the given stress increment. lution: