The cumulative frequency just greater than N/2 = 30 is 50 and the corresponding class isSTATISTICS15.29MarksCalculation of MedianNo. of studentsCumulative frequency0- 1010-30(Frequency)30-60152060-8080-90305085860Here, N = 60 . N/2 = 30N= Σ, =6030 - 60. Hence, 30 - 60 is the median class.1= 30, f = 30, F = 20, h = 30- FMedian = 1 + 2Now,x hfMedian = 30 +30 – 20x 30 = 4030EXAMPLE 3 If the median of the follozping frequency distribution is 46, find the tsonofrequencies.Variable:10 - 20 20-30 30-40 40 - 50 50- 60 60-70 70-80 Total229Frequency:1230652518SOLUTION Let the frequency of the class 30 - 40 be f, and that of the class 50 - 60 be f2. Thetotal frequency is 229.12 + 30 + f + 65 + f, + 25 + 18 = 229 = f, + f2 = 79It is given that the median is 46.Clearly, 46 lies in the class 40 - 50. So, 40 - 50 is the median class.1 = 40, h = 10, f = 65 and F = 12 + 30 + fi = 42 + f, N = 229Now,N- FMedian = 1 + xh229(42+ fi)x 1046 = 40 +46> 2f = 67 = f = 33.5 or 34 (say)%3DTherefore, f2 = 45.nd f = 45.Sir

From the given information, Consider, the frequency distribution can be expressed as: the missing…

EXAMPLE 3 If the median of the following frequency distribution is 46, find the missing frequencies. Variable: 10 - 20 20-30 30-40 40-50 50-60 60-70 70-80 Total 65 Frequency: 12 30 ? 25 18 229 SOLUTION Let the frequency of the class 30 - 40 be f, and that of the class 50- 60 be f2. The

EXAMPLE 3 If the median of the following frequency distribution is 46, find the missing frequencies. Variable: 10 - 20 20-30 30-40 40-50 50-60 60-70 70-80 Total 65 Frequency: 12 30 ? 25 18 229 SOLUTION Let the frequency of the class 30 - 40 be f, and that of the class 50- 60 be f2. The

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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