EXAMPLE 3 An object at the end of a vertical spring is stretched 8 cm beyond its rest position and released at time t = 0. (Note the downward direction is positive in the figure.) Its position at time t is s= f(t) = 8 cos(t) Find the velocity and acceleration at time t and use them to analyze the motion of the object. SOLUTION The velocity and acceleration are ds V = dt d(8 cos(t)) = 8- dt 8d(cos(t)) = dt dv a = dt 으(-8 sin(t)) = -8유(sin(t)) dt The object oscillates from the lowest point (s = 8 cm) to the highest point (s = -8 cm). The period of the oscillation is , the period of cos(t). The speed is Iv| = which is greatest when Isin(t)| = that is, when cos(t) = J. So the object moves fastest as it passes through its equilibrium position (s = 0). Its speed is 0 when sin(t) that is, at the high and low points. The acceleration a = = 0 when s = 0. It has greatest magnitude at the high and low points. See the graphs to the left.

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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-0-
b = 8
y
8.
6
4
-2
-4
-6
-8
2.
2.
Transcribed Image Text:-0- b = 8 y 8. 6 4 -2 -4 -6 -8 2. 2.
EXAMPLE 3
An object at the end of a vertical spring is stretched 8 cm beyond its rest position and released
at time t = 0. (Note the downward direction is positive in the figure.) Its position at time t is
s= f(t) = 8 cos(t)
Find the velocity and acceleration at time t and use them to analyze the motion of the object.
SOLUTION The velocity and acceleration are
ds
V =
dt
d(8 cos(t)) = 8-
dt
8d(cos(t)) =
dt
dv
a =
dt
으(-8 sin(t)) = -8유(sin(t))
dt
The object oscillates from the lowest point (s = 8 cm) to the highest point (s = -8 cm). The period of the
oscillation is
, the period of cos(t).
The speed is Iv| =
which is greatest when Isin(t)| =
that is, when
cos(t) =
J. So the object moves fastest as it passes through its equilibrium position (s = 0). Its
speed is 0 when sin(t)
that is, at the high and low points.
The acceleration a =
= 0 when s = 0. It has greatest magnitude at the high and low
points. See the graphs to the left.
Transcribed Image Text:EXAMPLE 3 An object at the end of a vertical spring is stretched 8 cm beyond its rest position and released at time t = 0. (Note the downward direction is positive in the figure.) Its position at time t is s= f(t) = 8 cos(t) Find the velocity and acceleration at time t and use them to analyze the motion of the object. SOLUTION The velocity and acceleration are ds V = dt d(8 cos(t)) = 8- dt 8d(cos(t)) = dt dv a = dt 으(-8 sin(t)) = -8유(sin(t)) dt The object oscillates from the lowest point (s = 8 cm) to the highest point (s = -8 cm). The period of the oscillation is , the period of cos(t). The speed is Iv| = which is greatest when Isin(t)| = that is, when cos(t) = J. So the object moves fastest as it passes through its equilibrium position (s = 0). Its speed is 0 when sin(t) that is, at the high and low points. The acceleration a = = 0 when s = 0. It has greatest magnitude at the high and low points. See the graphs to the left.
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