A mass weighing 24 pounds, attached to the end of a spring, stretches it 4 inches. Initially, the mass is released from rest from a point 4 inches below the equilibrium position. Find the equation of motion. (Use g = 32 ft/s? for the acceleration due to gravity.) x(t) =

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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Specifically a DiffEq problem. Question in pic below.

Answer: x(t) = (1/3)cos(4sqrt(6)(t)) ft

A mass weighing 24 pounds, attached to the end of a spring, stretches it 4 inches. Initially, the mass is released from rest from a point 4 inches below the equilibrium position. Find the equation of motion. (Use g = 32 ft/s? for the
acceleration due to gravity.)
x(t) =
Transcribed Image Text:A mass weighing 24 pounds, attached to the end of a spring, stretches it 4 inches. Initially, the mass is released from rest from a point 4 inches below the equilibrium position. Find the equation of motion. (Use g = 32 ft/s? for the acceleration due to gravity.) x(t) =
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