Example 24.31. Determine the ultimate net bearing capacity of the circular footing shown in Fig. 24.33. Also, compute the change in ultimate net bearing capacity, if the entire region is flooded, due 10 which the ground water level reaches ground level. 1.5 m 2m Clay Cu = 48 kPa 3.5 m $=0° Y 1.8 g/cc No = 5.7 W.T.

Q: Q/ For the following plan of building foundation, Determine immediate settlement at points (A) and…

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Q: square footing embedded at a depth of 2.0 meters

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Q: 1- Given Data Footing = 3.25 ksi = 60 ksi = 2.7 ksf Column = 350 Kips = 250 Kips D L fy 40 in × 30…

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Q: Circular foundation diameter B = 2m G.S. 1.0т Sand q = 150 kN/m² 0.5m W.T. Sand 0.5m Normally…

A: As per our company guidelines, we are supposed to answer only first three sub-parts. Kindly re-post…

Q: The 2.5 m x 3.5 m rectangular spread footing placed at a depth of 1.5 m supports a vertical load of…

A: To find:Factor of safety

Q: The specifications call for maximum allowable settlement of 25mm. Using the classical method…

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Q: Consider the given rectangular footing and soil having below mentioned properties: 1.5 m 1m] 785 D…

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Q: For the circular footing (ring) shown in the Figure 3, estimate the final consolidation settlement…

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Q: 3. A 1882KN load is carried by a 2.6m x 2.6m square footing at a depth of 1.4m in a 30 m deep sand…

A: Step 1

Q: example: (Total immediate settlement), Determine the total immediate settlement of the rectangular…

A: Calculate the stress at the base of the footing before placing the footing,  σ0 = γz     =20×1…

Q: The allowable settlement for the shown square footing is 2.5 cm. the footing is placed on clay soil…

A: Data given Find : Consolidation settlement

Methods to Determine Vertical Stress

The load applied to the soil is transferred to the underground. The presence of water at soil pores and solid grains above the soil are the primary components that are responsible for the effective load transfer. Due to the load acting, the internal component of the soil or the underground formations undergoes deformations or a tectonic shift. The amount of deformation depends upon the amount of load acting on the soil surface, which indeed, depends on the weight of everything present above the soil. Due to this, the underground soil element develops internal stresses which try to resist the tectonic changes.