i need the answer quickly Example 2.8: Determine the transfer function H(s) = V(s)/I(s) of the circuit in Fig. 2.18.%3D10I2 2sV(s)2ΩVo4ΩFig. 2.18.How did the equation becomeSolution:like this? Ineed a detailed(s +4)1,I, =s + 4 + 2 + 1/2ssolution pleaseBut2(s + 4)1,V. = 21, =%3Ds + 6 + 1/2sHence,V.(s)4s(s + 4)H(s) =1,(s)2s + 12s + 1ww

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Example 2.8: Determine the transfer function H(s) = V(s)/I(s) of the circuit in Fig. 2.18. + V(s) 2Ω 4Ω Fig. 2.18. How did the equation become like this? Ineed a detailed solution please Solution: (s+ 4)1 12 = s + 4 + 2 + 1/2s But 2(s + 4)1, V, = 212 = %3D s + 6 + 1/2s Hence, V(s) 4s(s+4) H(s) 1,(s) 2s + 12s + 1 ww (+)

Example 2.8: Determine the transfer function H(s) = V(s)/I(s) of the circuit in Fig. 2.18. + V(s) 2Ω 4Ω Fig. 2.18. How did the equation become like this? Ineed a detailed solution please Solution: (s+ 4)1 12 = s + 4 + 2 + 1/2s But 2(s + 4)1, V, = 212 = %3D s + 6 + 1/2s Hence, V(s) 4s(s+4) H(s) 1,(s) 2s + 12s + 1 ww (+)

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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