Example 2.19. Consider men who need to undergo a complicated surgery.The probability that they will survive for a year following surgery is only50%. If they do survive for a year, then they are fully cured and theirfuture mortality follows the pattern of general population.Suppose that for the general population, we have l60 = 89, 777, l61 =89, 015, and l70o =77,946.Calculate probabilities that(1) a man aged 60 who is just about to have surgery will be alive atage 70,(2) a man aged 60 who had surgery at age 59 will be alive at age 70,and(3) a man aged 60 who had surgery at age 58 will be alive at age 70.

In the given problem, the surgery is complicated as there is only 50% chance of survival for the…

Answered: Example 2.19. Consider men who need to…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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QUESTION 1 A retailer of Christmas trees has estimated the number of trees that he will sell during the next season. The folowing table summarizes the demands for trees and their respective probabilities: Probability (X) Demand 4 0,5 5 0.2 10 0,3 1.1. Is demand for trees a proper probability function? Why, or why not? 1.2. What is the probability that the demand for trees will be equal to 4? 1.3. What is the probability that the demand for trees will be equal to 10? 1.4. What is the probability that the demand for trees will be greater than 4? 1.5. What is the expected value of demand for trees? 1.6. What is the variance of the demand for trees?
In the game of roulette, a player can place a $7 bet on the number 32 and have a 138 probability of winning. If the metal ball lands on 32, the player gets to keep the $7 paid to play the game and the player is awarded an additional $245.Otherwise, the player is awarded nothing and the casino takes the player's $7. Find the expected value E(x) to the player for one play of the game. If x is the gain to a player in a game of chance, then E(x) is usually negative. This value gives the average amount per game the player can expect to lose.
Question 24
This subject is Engineering data analysis.
In the game of roulette, a player can place a $6 bet on the number 11 and have a ag probability of winning. If the metal ball lands on 11, the player gets to keep the $6 paid to play the game and the player is awarded an additional $210. Otherwise, the player is awarded nothing and the casino takes the player's $6. Find the expected value E(x) to the player for one play of the game. If x is the gain to a player in a game of chance, then E(x) is usually negative. This value gives the average amount per game the player can expect to lose. The expected value is $ (Round to the nearest cent as needed.)

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