Example 2: Consider the following given information. Use a = 0.01. Interpret the result. Null Hypothesis Alternative Hypothesis i = 124.5 s = 5 Ho: µ = 127 Ha: µ < 127 u = 127 n = 12
Example 2: Consider the following given information. Use a = 0.01. Interpret the result. Null Hypothesis Alternative Hypothesis i = 124.5 s = 5 Ho: µ = 127 Ha: µ < 127 u = 127 n = 12
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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Answer the questions with complete SOLUTION, GRAPH & ANSWERS, just like in the given example
Transcribed Image Text:Solution:
It is a one-tailed test since the alternative hypothesis uses the symbol
for greater than (>). And since o is known and n 2 30, we will use z-test. The
level of significance is 0.05.
From Table 1, the z-critical value is 1.645.
Thus, we have:
71.5 – 70
1.5
z =
8
0.8
V100
z = 1.875
1.645
z-critical value
The computed z-value is 1.875 which is greater than the critical
value of 1.645. Therefore, we reject the null hypothesis and support and
accept the alternative hypothesis that the population mean is greater
than 70.
Example 2:
Consider the following given information. Use a = 0.01. Interpret the result.
Null Hypothesis
Alternative Hypothesis
I = 124.5
Ho: µ = 127
Ha: μ < 127
µ = 127
n = 12
s = 5
Transcribed Image Text:3. A random sample of 16 drinks from a soft drink machine has the
following contents(ml):
250 280 290 265 270 280 280 300
275 295 300 285 290 300 250 260
The population mean content is 275 ml. Assume that the distribution
of the soft drinks contents be normal. Is there a significant difference
between the sample and the population mean contents of the soft
drinks? Use a 90% confidence level?
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