Example 2: A local community college professor was interested in interviewing students from her college to determine how much, on average, those students spend on textbooks each semester. She randomly sampled 47 students and found that they had spent an average of $214 on textbooks each semester with a standard deviation of $51. a) Construct and interpret an 87% confidence interval for the true mean amount of money that students at this particular community college spend on textbooks each semester. b) How would the interval that you created in part (a) compare to an 80% confidence interval for the same parameter? Calculate the new interval to justify your answer. c) How would the interval that you created in part (a) compare to a 96% confidence interval for the same parameter? Calculate the new interval to justify your answer.

Example 2: A local community college professor was interested in interviewing students from her college to determine how much, on average, those students spend on textbooks each semester. She randomly sampled 47 students and found that they had spent an average of $214 on textbooks each semester with a standard deviation of $51. a) Construct and interpret an 87% confidence interval for the true mean amount of money that students at this particular community college spend on textbooks each semester. b) How would the interval that you created in part (a) compare to an 80% confidence interval for the same parameter? Calculate the new interval to justify your answer. c) How would the interval that you created in part (a) compare to a 96% confidence interval for the same parameter? Calculate the new interval to justify your answer.

Name: Example 2: A local community college professor was interested in inte
Uploaded: 2024-03-20T07:07:12.000Z
Channel: Bartleby
Description: Example 2: A local community college professor was interested in interviewing students from hercollege to determine how much, on average, those students spend on textbooks each semester.She randomly sampled 47 students and found that they had spent

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: what would be the 90% confidence interval of the true proportion of young adults who have received…

A: Given that sample size is n = 190 And the sample proportion is 70% = 0.7 At 90% confidence level,…

Q: A national air traffic control system handled an average of 47,189 flights during 29 randomly…

A: The sample size is 29The sample mean is 47189The sample standard deviation is 6351We have to…

Q: A local news outlet reported that 56% of 600 randomly sampled Kansas residents planned to set off…

A: We have given that, Sample proportion (p̂) = 56% = 0.56 and sample size (n) = 600 Then, We will…

Q: a survey of 3088 adults aged 57 through 85 years, it was found that 87.1% of them used at least…

A: The formula for computing confidence interval is, n is the sample size and P is the proportion.

Q: An insurance company checks police records on 582 accidents selected random and notes that teenagers…

A: Given data, n=582 x=100 Create a 99.7 % confidence interval for the percentages of all auto…

Q: An issue of Time Style and Design reported on a poll conducted by Schulman Ronca & Bucuvalas Public…

A: (a)given that,possible chances (x)=410size(n)=603success rate ( p )= x/n = 0.6799point of estimate =…

Q: The internal auditing staff of a local manufacturing company performs a sample audit each quarter to…

Q: In a survey, 14 people were asked how much they spent on their child's last birthday gift. The…

Q: Find a 95% confidence interval for the proportion of all U.S. adults with household incomes of at…

A: We need to construct the 95%95\%confidence interval for the population proportion. We have been…

Q: In one community, a random sample of 25 foreclosed homes sold for an average of $443,776 with a…

A: From the provided information,Standard deviation (s) = 196739Sample mean (x̄) = 443776Sample size…

Q: In a survey, 15 people were asked how much they spent on their child's last birthday gift. The…

Q: In a survey of 3115 adults aged 57 through 85 years, it was found that 86.1% of them used at…

Q: Use this sample data to construct a 90% confidence interval for the mean number of targeted…

A: Given : Sample size = 20 Sample data: 79 145 147 160 116 100 159 151 156 126 137…

Q: Is the proportion of all people who went trick or treating who received fruit in addition to candy…

A: based on the calculation in question 9, we can say with 95% confidence that the true proportion of…

Q: In a survey, 1000 adults in a certain country were asked how many hours they worked in the previous…

A: Confidence interval used to obtain the range where the population true mean lies. It explain the…

Q: one with a 95% confidence level and the other with a 99.7% confidence level. Which interval is…

A: Confidence interval is probability, which refers that population parameter will fall within set of…

Q: #4. A college president commissioned a study to find the proportion of students enrolled at her…

Q: In Oct. 2008, scientists tested cord blood samples for 20 newborn infants in USA. The scientists…

A: Given information- Sample size, n = 20 Now, degree of freedom is given by- Degree of freedom, df = n…

Q: In a survey, 28 people were asked how much they spent on their child's last birthday gift. The…

A: It is given that Sample mean = 46 Sample standard deviation = 10 Sample size = 28

Q: Family Closeness. A study conducted among college students evaluated the connection between drug use…

Q: Suppose that Randy is an analyst for the bicyling industry and wants to estimate the asking price of…

A: The summary of the statistics is The degree of freedom is, Critical values: The t-critical values…

Q: search for the Ford Motor Company, you find that a random sample of 800 households includes 721 in…

A: At 98% confidence level, the z value is 2.33 which can be obtained by using the standard normal…

Q: A survey of 20 people asked, “If you’ve ever been married, how old were you when you were first…

Q: I asked 45 randomly selected WSU college students how many US states they had visited. The students'…

A: The sample size is 45, sample mean is 3.8 and standard deviation is 1.5. The degrees of freedom is,…

Q: . A sociologist develops a test to measure attitudes about public transportation, and 20 randomly…

A: Answer - A sociologist develops a test to measure attitudes about public transportation,…

Q: Two researchers conducted a study in which two groups of students were asked to answer 42 trivia…

A: given data group 1x¯1 = 25s1 = 4.5n1 = 200group 2x¯2 =19.6s2 = 4.3n2 = 20095% ci for μ1-μ2here i…

Q: Two researchers conducted a study in which two groups of students were asked to answer 42 trivia…

A: The mean and standard deviation for group 1 are x1=22sd1=3.5n1=200 The mean and standard deviation…

Q: survey conducted by Gallup in 2020 asked 1,102 randomly selected U.S. adults, "What do you think is…

A: We have given that Sample size n=1102 90% confidence interval. = (0.6773, 0.7227)

Q: If 64% of a sample of 550 people leaving a shopping mall claims to have spent over $25 create and…

A: Given, Sample size = 550 Sample proportion = 0.64 Critical value: Using z-table, the z-critical…

Q: In a survey, 14 people were asked how much they spent on their child's last birthday gift. The…

A: Given information- Sample size, n = 14 Mean, x-bar = $32 Standard deviation, s = $20 Confidence…

Q: A survey of credit card holders revealed that Americans carried an average credit card balance of…

A: M1=$3900M2=$3300n1=400n2=450σ1=$880σ2=$810

Q: QUESTION #2. In a Harris poll, adults were asked if they are in favor of abolishing the penny. Among…

Q: Data were collected on the amount spent by 64 customers for lunch at a major Houston restaurant.…

A: As per our guidelines we are supposed to answer only three subparts kindly post the remaining…

Q: In a survey, 22 people were asked how much they spent on their child's last birthday gift. The…

Topic Video

Question

Example 2: A local community college professor was interested in interviewing students from her
college to determine how much, on average, those students spend on textbooks each semester.
She randomly sampled 47 students and found that they had spent an average of $214 on
textbooks each semester with a standard deviation of $51.
a) Construct and interpret an 87% confidence interval for the true mean amount of money
that students at this particular community college spend on textbooks each semester.
b) How would the interval that you created in part (a) compare to an 80% confidence interval
for the same parameter? Calculate the new interval to justify your answer.
c) How would the interval that you created in part (a) compare to a 96% confidence interval
for the same parameter? Calculate the new interval to justify your answer.

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

Step 2

Step 3

Step 4

Step 5

Trending now

This is a popular solution!

Step by step

Solved in 5 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

$Hypothesis Tests and Confidence Intervals for Means$

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, statistics and related others by exploring similar questions and additional content below.

Similar questions

A Gallup poll of 1487 adults showed that 43% of the respondents have Facebook pages. Construct a 95% confidence interval for the proportion of adults who have a Facebook page.
In a random sample on 500 college students, 325 are currently taking a course online. What is the point estimate for the proportion of college students, currently taking a course online? ["", "", "", "", "", ""] Construct the 95% confidence interval for the proportion of college students, currently taking a course online. ["", "", "", "", ""]
In a survey, 24 people were asked how much they spent on their child's last birthday gift. The results were roughly bell-shaped with a mean of $36 and standard deviation of $15. Construct a confidence interval at a 90% confidence level.
See attachment
Suppose a study was conducted of community colleges in California to determine the average cost of tuition for in-state students. The study consisted of 45 community colleges from California. Based on the sample data, the average tuition was $1,440 and the standard deviation was $267. Use this information to construct and interpret a 92% confidence interval for the true average tuition of all California community colleges. Make sure to check any relevant assumptions and state how you determined whether or not they were satisfied (Be as specific as possible). Make sure to type your confidence interval in an interval format with each bound rounded to 3 decimal places [i.e. (12.345, 45.678)]
According to some car loan statistics, 44% of Americans are relying on an auto loan to pay for their cars. Assuming this finding to be based on a simple random sample of 1500 Americans, construct and interpret the 95% confidence interval for the population proportion of Americans who have a car loan.
A survey of 3737 randomly selected homeowners finds that they spend a mean of $73$73 per month on home maintenance with a standard deviation of $10$10 per month. Construct a 90%90% confidence interval for the mean amount of money spent per month on home maintenance by all homeowners. Round to the nearest cent.
Toby wants to know the average price of new cars at a particular dealearship. He randomly selects a sample of 31 cars and finds that the average price to be $19500$19500 with a standard deviation of $1640$1640. What is the 95% confidence interval for the mean price of cars at this particular dealership? With 95% confidence, we can say the true population mean price of cars at this dealership is between $____ and _____$ .Round to the nearest dollar
Suppose a sample of 9 customers spends an average of $200 with a standard deviation $20 what is a 95% confidence interval for the sample mean. Use the fact that 95% of sample means are within 2.306 standard errors of the sample mean.
A lawyer researched the average number of years served by 45 different justices on the Supreme Court. The average number of years served was 13.8 years with a standard deviation of 7.3 years. What is the 95% confidence interval for the average number of years served by all Supreme Court justices? Question 6 options: 1) (11.7,15.9) 2) (11.8,15.8) 3) (12.9,16.9) 4) (12.5,17.3)
At a large high school, an assistant principal wants to know how intelligent the students at the school are. An intelligence test is administered to an SRS of 50 students, out of over 2000 students. The mean score was 115 and the standard deviation was 15. Construct a 99% confidence interval for the mean score of all students in the school. A) (109.32, 120.69) B) (119.58, 123.50) C) (110.87, 129.41) D) Can not be determined from the information given.
The dataset "nurses" is a random sample of 1,000 cases from “Health Care Provider Credential Data” from Washington State Open Data Portal. In the sample, there are 418 CNA's and 278 of the CNA's have expired credentials. Use the statistics from the nurses dataset to answer the following question: "With 90% confidence, what percent of all CNA's on Washington State's healthcare provider list are expired?"