I asked 45 randomly selected WSU college students how many US states they had visited. The students' responses had a mean of 3.8 with a standard deviation of 1.5. Compute and interpret a 95% confidence interval for the true average number of states visited by students.

I asked 45 randomly selected WSU college students how many US states they had visited. The students' responses had a mean of 3.8 with a standard deviation of 1.5. Compute and interpret a 95% confidence interval for the true average number of states visited by students.

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

See similar textbooks

Related questions

Q: A random group of 36 people in Toms River were asked “how much money did you spend at the grocery…

A: Given: Sample mean x¯=149.50 Sample size (n) = 36 Sample standard deviation (s) = 22.50 Confidence…

Q: A study was commissioned to find the mean weight of the residents in certain town. The study…

A: Confidence interval : Confidence interval is a range of values it contains the true population…

Q: From a population of 540, a sample of 60 individuals is taken. From this sample, the mean is found…

A: Given that, From a population of 540, a sample of 60 individuals is taken. From this sample, the…

Q: 4. According to a recent poll of eight social networking sites, the averagemonthly visitor counnt…

A: In question, Given that in a poll of 8 networking sites the average monthly visitor count was 12.1…

Q: A group of 49 randomly selected students has a mean age of 22.4 years with a standard deviation of…

A: Sample mean = x̅ = 22.4 Sample size = n = 49 Sample S.D = s = 3.8 Standard Error = s/√n =…

Q: Among various ethnic groups, the standard deviation of heights is known to be approximately three…

A: Using Excel formula “=NORM.S.INV(1-(0.04/2))”, the critical value for 96% confidence level is…

Q: Suppose you use simple random sampling to select and measure 47 dogs' weights, and find they have a…

A: Given, mean is 78 and standard deviation is 13.5. Sample number is 47. We with use one sample z…

Q: 5. A researcher surveyed of 300 young adults ages 18-29 found that on average, those surveyed sent…

A: 5. Given that, n=300x¯=67.7s=23.6 Confidence level=90% Significance level=1-0.90-0.10…

Q: 2. A random sample of 85 group leaders, supervisors, and similar personal revealed that a person…

A: Introduction: The approach to determining the population distribution average is by utilizing a…

Q: A local police department made an effort to determine the average speed of automobiles travelling…

Q: Give a 95% confidence interval for the average value of all works of art of this kind.

A: Given , Mean x=5139 Standard deviation S=640 Sample size n=20 df=n-1…

Q: A researcher wishes to determine the average take-home pay of a part-time college student. He takes…

A: The objective of this question is to calculate the 95% and 99% confidence intervals for the average…

Q: A random sample of 40 home theater systems has a mean price of $500 and a standard deviation of $60.…

A: Construct the 99% confidence interval for the population mean The 99% confidence interval for the…

Q: pharmaceutical company wanted to estimate the population mean of monthly sales for their 250 sales…

A: Sample size n=40Sample mean=10000Standard deviation=1000

Q: 6. A food snack manufacturer samples 7 bags of pretzels off the assembly line and weighs their…

A: The confidence interval measure the range where the true population parameter exist. If the…

Q: A study was commissioned to find the mean weight of the residents in certain town. The study…

A: It is given that the a random sample of 123 residents and found the mean weight to be 187 pounds…

Q: Construct a 95% confidence interval for the ,ean number of hours of watching streaming videos…

A: given: mean=18.5 standard deviation = 3.2 we need to construct 95% CI for mean number of hours

Q: C2. Average years of education are reported by social class based on data from the GSS 2018. Mean…

A: Given data

Q: C. Find a 95% confidence interval for the average life time of all the television sets produced by a…

Q: Suppose a sample of 30 LCC students are given an IQ test. The sample has a standard deviation of…

A: Given the following information- n=30s=12.24s2=149.82

Q: A random sample of 42 business students required an average of 43.4 minutes to complete a statistics…

Q: survey asked 8 adults how many years of education they had. The sample mean was 12.90 with a sample…

Q: 1. A professor is interested in how long the average biostat student studies per night, so he asked…

A: Given data: n = 10 Data: 3, 4.5, 6, 5.5, 5, 4, 3, 2.5, 5, 3 hours. Confidence level = 90%…

Q: the following random sample was selected from a normal distribution: 11, 16, 3, 13, 18, 18, 16, 19,…

A: Given data is11, 16, 3, 13, 18, 18, 16, 19, 17, 11sample size(n)=10

Q: An administrator in charge of undergraduate education on a large campus wanted to estimate the…

A: Introduction: The 100 (1 – α) % confidence interval for the population mean, μ, when the population…

Q: A survey of first time homeowners found that the sample mean annual income was $53,000. Assume that…

Q: . A sociologist develops a test to measure attitudes about public transportation, and 20 randomly…

A: Answer - A sociologist develops a test to measure attitudes about public transportation,…

Q: If the mean flying time for a sample of 65 pilots was 15.6 hours per month, and the population…

Q: A credit counseling agency wants to estimate the mean amount of credit card debt held by Americans.…

A: Here we need to construct a 90% confidence interval for the population mean.

Q: A study of 81 bolts of carpet showed that their average length was 77.5 yards. The standard…

Q: A study of 96 bolts of carpet showed that their average length was 77.5 yards. The standard…

A: GivenMean(x)=77.5sample size(n)=96standard deviation(s)=1.6α=1-0.99=0.01α2=0.005zα2=z0.05=2.58

Q: A professor wants to estimate how many hours per week students study. A simple random sample of 78…

A: From the standard normal table, the z* value for 90% level is 1.645.

Q: for a sample of 57 that has a mean of 6200 and a standard deviation of 254, calculate the 95%…

Q: or a sample of 121 that has a mean of 6540 and a standard deviation of 780, calculate the 90%…

Q: To determine the views of students on a particular campus about fraternities, an 11-point attitude…

Q: college admissions officer takes a simple random sample of 80 entering freshmen and computes their…

Q: A study was commissioned to find the mean weight of the residents in certain town. The study…

Q: A small business wanted to estimate the mean income from their customers. They took a sample of 256…

A: We have to find the 90% confidence interval estimate for the population mean income of their…

Q: A study compared the cost of restaurant meals when people pay individually versus splitting the bill…

Concept explainers

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.

Question

I asked 45 randomly selected WSU college students how many US states they had visited. The students' responses had a mean of 3.8 with a standard
deviation of 1.5. Compute and interpret a 95% confidence interval for the true average number of states visited by students.

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

$Point Estimation, Limit Theorems, Approximations, and Bounds$

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, probability and related others by exploring similar questions and additional content below.

Similar questions

To decide what personnel requirements should be enforced, a hospital manager wants to estimate the mean number of people who are admitted to the emergency room during a 24-hour period. The director randomly selects 48 different 24-hour periods and counts the number of admissions for each. In his sample, the sample mean is 296 and the sample standard deviation is 89. Estimate the mean number of admissions per 24-hour period with a 95% confidence interval.
1. A company surveyed its employees to determine what the new daily meal allotment dollar amount should be. Of the 159 employees, 94 responded. Pat’s supervisor asked what the recommended dollar amount should be. Pat could take the mean of the 94 responses or calculate a confidence interval about the mean using those 94 responses. Which action of the two (don’t go outside these choices) would give the supervisor a better idea of what the true mean is, and why?
A study of 96 bolts of carpet showed that their average length was 77.5 yards. The standard deviation of the population is 1.6 yards. Which of the following is the 90% confidence interval for the mean length per bolt of carpet?
Suppose a study was conducted of community colleges in California to determine the average cost of tuition for in-state students. The study consisted of 45 community colleges from California. Based on the sample data, the average tuition was $1,440 and the standard deviation was $267. Use this information to construct and interpret a 92% confidence interval for the true average tuition of all California community colleges. Make sure to check any relevant assumptions and state how you determined whether or not they were satisfied (Be as specific as possible). Make sure to type your confidence interval in an interval format with each bound rounded to 3 decimal places [i.e. (12.345, 45.678)]
The average weight of 31 randomly selected minivans was 4150 pounds. The sample standard deviation was 480 pounds. Find the 99 percent confidence interval of the true population mean weight of minivans.
According to a November 2014 Winthrop poll, of 852 polled SC residents, 222 of them said they plan to spend less on gifts this holiday season. Suppose 30% of all SC residents will spend less this holiday season. Identify the standard deviation of (all possible) sample proportions for SC resident who will spend less.
Given the following: Sample Mean = 84.3 Population Variance = 144 Sample size = 35 a. Calculate a 90% confidence interval for the mean. Interpret this interval. b. Calculate a 99% confidence interval for the mean. c. Explain the relationship between Confidence Levels and the resulting intervals.
Suppose a sample of 30 students are given an IQ test. The sample has a standard deviation of 12.23 points. Assuming IQ test score follow a normal distribution, suppose the researcher wishes to obtain a 90% confidence interval for the population standard deviation.
An internet study was mailed to 2336 subjects randomly. 1108 surveys were returned. Construct a 95% confidence interval for the proportion of the returned surveys. identify the margin of error E.
Afra is working in a bank. She has randomly contacted 36 customers and has examined their average annual salary. She found that the average salary of this sample of customers is $68200 with a sample standard deviation of $2375. She needs to report the population average at 95% confidence interval. What is the range that she should report?
A survey of 4646 randomly selected homeowners finds that they spend a mean of $66$66 per month on home maintenance with a standard deviation of $12$12 per month. Construct a 95%95% confidence interval for the mean amount of money spent per month on home maintenance by all homeowners. Round to the nearest cent.