Example 2: A 1.00 kg sample of Sb;S3 (s) and a 10.0 g sample of H2 (g) are allowed to react in a 25.0 L container at 713 K. At equilibrium, 72.6 g of H2S (g) are present. Calculate the Kp for the following reaction (@ 713 K): Sb2S3 (s) + 3 H2 (g) <→ 2 Sb (s) + 3 H2S (g) Note: There are solids in this reaction... Think about how that affects the Kp expression.

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Chapter1: Chemical Foundations
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Hey,

The issue I am having here is calculating the partial pressure, if I use 

P=(n/V)*R*T then I get the partial pressure of H2 as 23.2 but according to the teacher it should be 11.585 so instead of just calculating the the total moles of H2 in the reaction should n be a molar fraction? 

Example 2: A 1.00 kg sample of Sb;S3 (s) and a 10.0 g sample of H2 (g) are allowed to react in a
25.0 L container at 713 K. At equilibrium, 72.6 g of H2S (g) are present. Calculate the Kp for the
following reaction (@ 713 K):
Sb2S3 (s) + 3 H2 (g) <→ 2 Sb (s) + 3 H2S (g)
Note: There are solids in this reaction... Think about how that affects the Kp expression.
Transcribed Image Text:Example 2: A 1.00 kg sample of Sb;S3 (s) and a 10.0 g sample of H2 (g) are allowed to react in a 25.0 L container at 713 K. At equilibrium, 72.6 g of H2S (g) are present. Calculate the Kp for the following reaction (@ 713 K): Sb2S3 (s) + 3 H2 (g) <→ 2 Sb (s) + 3 H2S (g) Note: There are solids in this reaction... Think about how that affects the Kp expression.
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