/Example 19.9. Taking fifth order differences of U, to be constant and given Up, Uy Uy „U5, prove that U1=c+ 25 25(c-b) + 3(a – c) 256 where a = Uo + Us, b=U, + U4, c=U2+ Uz.

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Example 19-9. Taking fifth order differences of U, to be constant and given Ug, U1, U
U5, prove that
1
U 1=
25(c-b) + 3(a c)
256
where a = Uo + U5, b= U1+ U4, c=U2+ Uz-
Transcribed Image Text:Example 19-9. Taking fifth order differences of U, to be constant and given Ug, U1, U U5, prove that 1 U 1= 25(c-b) + 3(a c) 256 where a = Uo + U5, b= U1+ U4, c=U2+ Uz-
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