Example 17.1 A constant voltage of frequency, 1 MHz is applied to a lossy inductor (r in series with L), in series with a variable capacitor, C (Fig. 17.3). The current drawn is maximum, when C = 400 pF; while current is reduced to (1/2) of the above value, when C = 450 pF. Find the values of r and L. Calculate also the quality factor of the coil. and the bandwidth. R

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The band width is given by Af f,-fi-R/(2x L)
It can be observed that, to improve the quality factor (Q) of a coil, it must be designed
to have its resistance, R as low as possible. This also results in reduction of band width
and losses (for same value of current). But if the resistance, R cannot be decreased, then
Q will decrease, and also both band width and losses will increase.
Example 17.1
A constant voltage of frequency, 1 MHz is applied to a lossy inductor (r in series with
L). in series with a variable capacitor, C (Fig. 17.3). The current drawn is maximum,
when C = 400 pF; while current is reduced to (1/2 ) of the above value, when C = 450
pF. Find the values of r and L. Calculate also the quality factor of the coil, and the
bandwidth.
R
V
f= 1 MHz
Fig. 17.3 Circuit diagram
Solution
近
Transcribed Image Text:The band width is given by Af f,-fi-R/(2x L) It can be observed that, to improve the quality factor (Q) of a coil, it must be designed to have its resistance, R as low as possible. This also results in reduction of band width and losses (for same value of current). But if the resistance, R cannot be decreased, then Q will decrease, and also both band width and losses will increase. Example 17.1 A constant voltage of frequency, 1 MHz is applied to a lossy inductor (r in series with L). in series with a variable capacitor, C (Fig. 17.3). The current drawn is maximum, when C = 400 pF; while current is reduced to (1/2 ) of the above value, when C = 450 pF. Find the values of r and L. Calculate also the quality factor of the coil, and the bandwidth. R V f= 1 MHz Fig. 17.3 Circuit diagram Solution 近
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