Example 11: A d.c. generator with 480 armature conductors supplies a current of 144 A. The brushes are given an actual lead of 10o. Calculated demagnetizing amp turns per pole found to be 28 percentage of cross magnetizing amp turns per pole, determine number of pole if armature field is wave wound Solution :

Example 11: A d.c. generator with 480 armature conductors supplies a current of 144 A. The brushes are given an actual lead of 10o. Calculated demagnetizing amp turns per pole found to be 28 percentage of cross magnetizing amp turns per pole, determine number of pole if armature field is wave wound Solution :

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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The total conductor of the direct current generator shown in the figure is 1440. The length of the armature is 30cm, the magnetic flux of a pole is 0.8 Tesla and the armature rotates at a speed of 4 m / s. Find the value of the voltage generated by the armature according to the position in the figure.
The DC shunt generator with the terminal voltage 300 V, armature drop 8 V and the each brush drop 2 V, then the value of generated emf is
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➡ A four-pole Series connected generator has a lap connected armature with 728 conductors. If the generator supplies one hundred incandescence lamp (100 V, 60W). The series field and armature resistance are 0.2 ohms and 0.015 ohms respectively. Find the series field current.
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