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Example 1: Graphical determination of partial molar volume. Using Equations 23 or 26; Prove that partial molar volume of component 1 in a binary mixture equals BD at the composition x2. A ÎM (Molar Volume of Mixture)

Example 1: Graphical determination of partial molar volume. Using Equations 23 or 26; Prove that partial molar volume of component 1 in a binary mixture equals BD at the composition x2. A ÎM (Molar Volume of Mixture)

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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PM - XA dxA PB @M + XA dxB M (23) d@M since dxA 3D —-dxв 3D Фв B M Since dx, = -dxB, Equation 19 can be also rewritten as: 4 dộM = dộm = (@B – Pa)dxB = Фв — ФА (24) dxB dộm = -Padxg + @gdxa Combining Equations 17 and 24 gives: dộm — фм — Хв (25) (d@m + + (Хд + Хв)ФА dxB PA PM = XAPA + xB dxB (26) since dxA 3D -dхв — ФА%3D Фм + хв dxB dxA PA = PM – XB А
Transcribed Image Text:PM - XA dxA PB @M + XA dxB M (23) d@M since dxA 3D —-dxв 3D Фв B M Since dx, = -dxB, Equation 19 can be also rewritten as: 4 dộM = dộm = (@B – Pa)dxB = Фв — ФА (24) dxB dộm = -Padxg + @gdxa Combining Equations 17 and 24 gives: dộm — фм — Хв (25) (d@m + + (Хд + Хв)ФА dxB PA PM = XAPA + xB dxB (26) since dxA 3D -dхв — ФА%3D Фм + хв dxB dxA PA = PM – XB А
Example 1: Graphical determination of partial molar volume. Using Equations 23 or 26; Prove that partial molar volume of component 1 in a binary mixture equals BD at the composition x2. A 1 VM (Molar Volume of Mixture)
Transcribed Image Text:Example 1: Graphical determination of partial molar volume. Using Equations 23 or 26; Prove that partial molar volume of component 1 in a binary mixture equals BD at the composition x2. A 1 VM (Molar Volume of Mixture)
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