Examine the following reaction. 4 Al 203 (s) + 3 CI (aq) = 8 AI( s) +3 CIO 4 (aq) What is the equilibrium expression for the reaction? O K = [Al2O3]/ [AI] O K = [CI]/[CIO4'] O K = [AI]® [CIO4 / ([Al,Og]* [CI]°) OK = [CI']3 /[CIO 4 13 O K = [CIO4]³/[CI]3 O K = [CIO4]/[CIr] O K = [Al2O3]* [CI]/ ([AI]® [CIO419) O K = [Al] [CIO4]/ ([Al203] [CI]) O K = [AI]/[Al203] O K = [Al2O3][CI]/ ([AI] [CIO4"]) %3D %3D %3D %3D %3D
Examine the following reaction. 4 Al 203 (s) + 3 CI (aq) = 8 AI( s) +3 CIO 4 (aq) What is the equilibrium expression for the reaction? O K = [Al2O3]/ [AI] O K = [CI]/[CIO4'] O K = [AI]® [CIO4 / ([Al,Og]* [CI]°) OK = [CI']3 /[CIO 4 13 O K = [CIO4]³/[CI]3 O K = [CIO4]/[CIr] O K = [Al2O3]* [CI]/ ([AI]® [CIO419) O K = [Al] [CIO4]/ ([Al203] [CI]) O K = [AI]/[Al203] O K = [Al2O3][CI]/ ([AI] [CIO4"]) %3D %3D %3D %3D %3D
Chemistry & Chemical Reactivity
10th Edition
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter19: Principles Of Chemical Reactivity: Electron Transfer Reactions
Section: Chapter Questions
Problem 88GQ: Calculate equilibrium constants for the following reactions at 208 K. Indicate whether the...
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Examine the following reaction.
4 Al 203(s)+3cI (aq) s 8Al(s) + 3 CIO 4 (aq)
What is the equilibrium expression for the reaction?
O K = [Al2O3]/[AI]
O K = [CI']/[CIO4]
O K = [AI]® [CIO4³/ [AI½O3]* [CI]°)
OK = [CI ]3 /[CIO 4 ]3
O K = [CIO4]/[CI]3
O K = [CIO4']/[CI']
O K = [Al,O3]* [CIr]³ / ([AI]® [CIO4]°)
O Kc = [AI] [CIO4]/([AI½O3] [CI'])
O K = [AI] /[Al,03]
O K = [Al2O3] [CI] / ([AI] [CIO4])](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F325ccfbf-0912-4624-82ab-4204db58e4ba%2F427e3dcd-6df5-4551-b264-2c59e15d72d8%2F4faufvx.bmp&w=3840&q=75)
Transcribed Image Text:Current Attempt in Progress
Examine the following reaction.
4 Al 203(s)+3cI (aq) s 8Al(s) + 3 CIO 4 (aq)
What is the equilibrium expression for the reaction?
O K = [Al2O3]/[AI]
O K = [CI']/[CIO4]
O K = [AI]® [CIO4³/ [AI½O3]* [CI]°)
OK = [CI ]3 /[CIO 4 ]3
O K = [CIO4]/[CI]3
O K = [CIO4']/[CI']
O K = [Al,O3]* [CIr]³ / ([AI]® [CIO4]°)
O Kc = [AI] [CIO4]/([AI½O3] [CI'])
O K = [AI] /[Al,03]
O K = [Al2O3] [CI] / ([AI] [CIO4])
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