Exam 41-2021 : Ansner all questionsOl:A: The following data apply to a 100-AW 250-V six-pole, 900-rpmcompound generator dong-shunt connection: No-load rotationallosses = 3840 W Armature resistance - 0.0122, Series-field resistance- 0.0042, Commutating-pole ficld resistance = 0.004n, Shunt-fieldcurrent = 2.60 A. Assume a stray-load loss equal to 1% of the outputand Calculate the rated-load efficiency.

Calculate the load current of the generator. IL=PoutV=100×03 W250 V=400 A

Exam -2021 ARall.stio Anser all questions QLA: The following data apply te a 100-AW 250-V sis-pole, 900-rpm compound generator dong-shunt connection: No-load rotational losses 3840 W Armature resistance-0.012, Series-field resistance -0.004, Commutating-pole ficld resistance - 0.004, Shunt-field current = 260 A. Assume a stray-lad loss equal to 1% of the output and Caleulate the rated-load eficiency.

Exam -2021 ARall.stio Anser all questions QLA: The following data apply te a 100-AW 250-V sis-pole, 900-rpm compound generator dong-shunt connection: No-load rotational losses 3840 W Armature resistance-0.012, Series-field resistance -0.004, Commutating-pole ficld resistance - 0.004, Shunt-field current = 260 A. Assume a stray-lad loss equal to 1% of the output and Caleulate the rated-load eficiency.

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

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