Exactly 1.00 mol CIF3 is placed in an empty 1.00-L container (without any products initially) and allowed to reach equilibrium described by the equation 2 CIF3 (9) = C2 (9) + 3 F2 (9) at 380 K. After the reaction reaches equilibrium, the amount of F2 becomes 0.810 mol, what is the value of the equilibrium constant, Ke, for this reaction at 380 K? Your answer should have 3 significant figures.
Exactly 1.00 mol CIF3 is placed in an empty 1.00-L container (without any products initially) and allowed to reach equilibrium described by the equation 2 CIF3 (9) = C2 (9) + 3 F2 (9) at 380 K. After the reaction reaches equilibrium, the amount of F2 becomes 0.810 mol, what is the value of the equilibrium constant, Ke, for this reaction at 380 K? Your answer should have 3 significant figures.
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
Transcribed Image Text:Exactly 1.00 mol CIF3 is placed in an empty 1.00-L container (without any products initially) and allowed to reach
equilibrium described by the equation 2 CIF3 (g) = Cl2 (g) + 3 F2 (g) at 380 K.
After the reaction reaches equilibrium, the amount of F2 becomes 0.810 mol, what is the value of the equilibrium
constant, Ke, for this reaction at 380 K? Your answer should have 3 significant figures.
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