Ex2: Locate the centroid y of the homogeneous solid formed by revolving the shaded area about the y axis 0.5 m Sol:
Q: An infinite sheet with surface charge density a=5.6 µC/m² bisects a Gaussian surface in the shape of…
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Q: 6. What is the electric flux through the surface shown in this figure? Where 0 = 25°; E = 100 N/C;…
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Q: A solid conducting sphere with radius R = 5.0 cm carries a positive charge Q = 5.0 nC. The sphere is…
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Q: . Find the surface area of that portion of the paraboloid z = 4-x² - y² that is above the xy plane.
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Q: 2a A sphere of radius R=2a is made of a nonconducting material that has a uniform volumetric charge…
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Q: What is the net electric flux through the closed cylindrical surface(of Radius=R) shown And What is…
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Q: A closed surface with dimensions a=b%3D0.40 m and c=0.60 m is located as in the figure below. The…
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Q: A closed surface with dimensions a=b=0.40 m and c=0.60 m is locate as in the figure below. The left…
A: The flux is equal to
Q: Consider the following conversation: Student 1: "The net flux through the surface in each case must…
A: flux=field ×areastudent 1:as per by gauss law , net flux through a closed surface depend only on…
Q: Q2. Transform the vector V = pâp + zâz to Spherical Coordinates. What is the flux of this vector…
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Q: Q1. We have an electric Flux density D = 0.3² r nC/m² in free space. Find the total flux leaving the…
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Q: 1. Find the flux of the vector field F(x, y, z) = (x, 2z, 3y) outward across the surface of the…
A: Given Data: Vector field F(x,y,z) = x,2z,3y.Vertices = (0,0,0), (1,0,0), (0,2,0), (0,0,3). To…
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Q: The electric charge q in the figure is suspended inside the volume of the tetrahedron. The…
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- B4A Positive electric charge Q is distributed uniformly throughout the volume of an insulating solid sphere with radius a (picture). By using Gauss Law, find the magnitude of the electric field at a point P, a distance r from the center of the sphere where: a) r<a b) r>aWhat is the net electric flux through the closed cylindrical surface(of Radius3R) shown And What is the net charge inside this cylindrical surface? Given that E=160 N/C and R=0.45 m. E 2R Select one: O a. 101.79 Nm^2/C, 9*10^(-10) C O b.452.39 Nm^2/C, 4*10^(-9) C O c. 203.58 Nm^2/C, 1.8*10^(-9) C O d. net flux is zero and net charge is zero O e. 226.2 Nm^2/C, 2*10^(-9) C
- Q4. The square surface shown in Figure given below measures 3.2 mm on each side. It is immersed in a uniform electric field with magnitude E = 1800 N/C and with field lines at an angle of 0 = 35° with a normal to the surface, as shown. Take that normal to be directed "outward," as though the surface were one face of a box. Calculate the electric flux through the surface. NormalQ2: Answer only one (a) In Figure below, consider a plane surface in a uniform electric field, where d = 15 cm and 0 = 70°. Find the magnitude of the electric field if the net flux through the surface is 6 N. m²/C, (b) In the same figure, find the electric flux through the plane surface if 0 = 60°, E = 350 N/C, and d = 5 cm. The electric field is uniform over the entire area of the surface. EA closed surface with dimensions a=b=D0.40 m and c=0.60 m is located as in the figure below. The left edge of the closed surface is located at position x= a. The electric field in the region is non-uniform and is given by E=(3.0+ 44x2 ) i N/C, where x is in meters. Calculate the net electric flux leaving the closed surface? b- Select one: OA. 5.91 O B. 1.41 OC. 14,71 OD. 4.22 OE 10.31
- 2. Consider an insulating spherical shell of inner radius a and outer radius b. a. If the shell has a net charge Q uniformly distributed over its volume, find the vector electric field in all regions of space (r b) as a function of r. b. Now assume that the shell has a non-uniform charge density given by r2 p(r) = Po ab What is the net charge of the shell? c. For the charge distribution in part (b), find the vector electric field in all regions of space (r b) as a function of r.c) For the same cylindrical shell as in the previous problem, draw and label a Gaussian surface and use Gauss's Law to find the radial electric field in the region r > R2. You may take the positive direction as outward. 0 E (r > R2) =Solve for the net flux through each closed surface. -20 x 10c 3.0 x 10c (a) -3.0 x 106C 4.0 x 10c 5.0 x 106C (b) -2.0 x 10C (c) End cap of area 4.0 X 104 m a= 2.0 X 10 Cim? (d) Conductor + + + + + + +
- 9A. A metal sphere of radius R and charge Q is surrounded by concentric metallic spherical shell of inner radius R1 > R, outer R1 > R1 and load Q1 . This system is surrounded by another concentric metallic spherical shell of inner radius R2 > R1, outer R2 > R2 and of load Q2 . Using suitably chosen Gaussian spherical surfaces, find the charge on the spherical surfaces with radii R, R1, R1, R2, R25. Let F = -9zi+ (xe"² – 2xe²²)+ 12 k. Find ſg F .dø and let S be the portion of the plane 2x + 3z = 6 that lies in the first octant such that 0 < y < 4 (see figure to the right), oriented upward. (a) Explain why the formula F à cannot be used to find the flux of F through the surface S. Please be specific and use a complete sentence.A vector field is given by F = y'e*i - x*yj - xtan-'yk use the divergence (Gauss") theorem, to calculate the flux of F through the surface S of the solid D bounded by the circular Cylinder x? + y? = 4, and the planes z = 0 and z = 3. z-3 %3D