For the same cylindrical shell as in the previous problem, draw and label a Gaussian surface and use Gauss's Law to find the radial electric field in the region r > R2. You may take the positive direction as outward.
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- provide a correct and well explained solutionWe have calculated the electric field due to a uniformly charged disk of radius R, along its axis. Note that the final result does not contain the integration variable r: R. Q/A 2€0 Edisk (x² +R*)* Edisk perpendicular to the center of the disk Uniform Q over area A (A=RR²) Show that at a perpendicular distance R from the center of a uniformly negatively charged disk of CA and is directed toward the disk: Q/A radius R, the electric field is 0.3- 2€0 4.4.1bA Gaussian surface in the form of a hemisphere of radius r lies in a uniform electric field of magnitude E. The surface encloses no net charge. At the (flat) base of the surface, the field is perpendicular to the surface and directed into the surface. NOTE: Express your answers in terms of the given variables, using when needed. (a) What is the flux through the base of the surface? Φ (b) What is the flux through the curved portion of the surface? Φ =
- A uniformly charged conducting sphere of 1.2m diameter has a surface charge density of 1.8µC/m?. Find the net charge on the sphere. b. What is the total electric flux leaving the sphere? What is the magnitude of the electric field at point P, 0.7m from the center of the sphere?Which describes the flux of an electric field that is tangent to a section on a closed surface? O The flux is negative. O The flux is positive. O The flux is zero.A charged particle is located at the center of two concentric conducting spherical shells, as shown below. The inner shell (in blue) has inner and outer radii a and b; the outer shell (in green) has radii c and d. Both shells may also carry a net charge. The plot shows the electric flux of a Gaussian spherical surface centered on the particle as a function of the radius r. Using Gauss’s law and the plot, find expressions for the following (in terms of Φ0): (a) The charge of the particle in the center (b) The net charge on the blue conducting shell (c) The net charge on the green conducting shell
- Gaussian surface 1 has twice the area of Gaussian surface 2. Both surfaces enclose the same charge Q. Is the electric flux through surface 1 greater than, less than, or the same as the electric flux through surface 2?Problem 2 Consider the Gaussian surface shown in Figure 2. A uniform external electric field E, having magnitude 3.20 x 103 N/C and parallel to the xz plane with an angle of 36.87° measured from the +x axis toward the +z axis, enters through face 1 (back face). In addition, a uniform electric field E, of magnitude 6.40 x 103 N/C traveling in the same direction as E, , flows outwardly through face 2 (front face). 0,45 m 0,30 m En 0.50 m Figure 2. Gaussian surface in the form of a prism through which two fields pass.A conducting sphere witha net charge Q and radius a sits inside a hollow conducting sphere with a net charge q, inside radius b and ouside radius c. What is the electric field as a function of position? Include answer for r < a, a < r < b, b < r< c and r>c