Ex. 1840. Given two voltage functions with phases in degrees: V1=44sin(26t+74) V2=34cos(26t+41). Determine: V1_phasor=Aexp(jB) and V2_phasor=Cexp(jD) and V3_phasor=V1+V2=Eexp(jF). Express your angles in degrees between -90 and +90. Answers: A,B (deg),C,D (deg),E,F (deg). ans:6
Ex. 1840. Given two voltage functions with phases in degrees: V1=44sin(26t+74) V2=34cos(26t+41). Determine: V1_phasor=Aexp(jB) and V2_phasor=Cexp(jD) and V3_phasor=V1+V2=Eexp(jF). Express your angles in degrees between -90 and +90. Answers: A,B (deg),C,D (deg),E,F (deg). ans:6
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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Ex. 1840. Given two voltage functions with phases in degrees: V1=44sin(26t+74) V2=34cos(26t+41). Determine: V1_phasor=Aexp(jB) and V2_phasor=Cexp(jD) and V3_phasor=V1+V2=Eexp(jF). Express your angles in degrees between -90 and +90. Answers: A,B (deg),C,D (deg),E,F (deg). ans:6
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The question states the angle must be within the range -90 to +90 how do I convert it to that
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