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EX: Find the F.T. of the triangular pulse : g(t) = AA ( \ ) Sols Apply differentiation property of F-T 2 get) = 2 A S(t+1) _4A S(t) + 2A S(t-1) The F.T for the both sides gives (jw)²2 G(w) = 2A (0-2 +2²²) juz (JW) GCW) - 4A Hello expert, I want you to explain how he got the value inside the circle. Can you explain step by step and in a clear line, please? 들 -+) A 1/4 800)-A () 24-9c 들 io N/H

EX: Find the F.T. of the triangular pulse : g(t) = AA ( \ ) Sols Apply differentiation property of F-T 2 get) = 2 A S(t+1) _4A S(t) + 2A S(t-1) The F.T for the both sides gives (jw)²2 G(w) = 2A (0-2 +2²²) juz (JW) GCW) - 4A Hello expert, I want you to explain how he got the value inside the circle. Can you explain step by step and in a clear line, please? 들 -+) A 1/4 800)-A () 24-9c 들 io N/H

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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EX: Find the F.T. of the triangular pulse: g(t) = AA (+) Sols Apply differentiation property of F-T g(t) = 2A S(t+1) - 4A S(t) + 2A S(t-1) The F.T for the both sides aiver (-) (jw) ² G(W) = 24 (² (JW) GCW) - 4A て 4A/e - j들 -j들 2 2+ A 0 8 (1) - A() =gcu [ Hello expert, I want you to explain how he got the value inside the circle. Can you explain step by step and in a clear line, please? ot
Transcribed Image Text:EX: Find the F.T. of the triangular pulse: g(t) = AA (+) Sols Apply differentiation property of F-T g(t) = 2A S(t+1) - 4A S(t) + 2A S(t-1) The F.T for the both sides aiver (-) (jw) ² G(W) = 24 (² (JW) GCW) - 4A て 4A/e - j들 -j들 2 2+ A 0 8 (1) - A() =gcu [ Hello expert, I want you to explain how he got the value inside the circle. Can you explain step by step and in a clear line, please? ot
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