2-Full Adder CFA) Application for the H.A. are limited. The H.A is no Sufficient for adding more than two one-bit numbers. Full Adder is a logic circuit that can add 3- bit and have two outputs. These outputs are the sum of three bits inputs and the second output is carry of them. The truth table and the block diagram are shown below:- RBC SG -S (sum) 00 0 FA 00 Cin -C (carry out) 0 -Carry input -0-00 - From the truth table:- S=1,2,4,7 = ABC ABC ABC + ABCin =ACBcin+B+ A (Bar+ Bcin) = Ā (B@ Cin) + A(B@Cin) = Ŕ (B @ Cin) + R (B&Cin) S = ABB Cin Co= {3,5,6,7 = = ABCin+ABCin+ ABCin + ABC ABC Cint Cin)+ Cin (AB+AB) = AB+ Ch(AGB) Cin= Cin Co EX:- Design H.A. using Comparators only:- Solution: HA S-AB+ AB- AB B = AØB ] C. AB المعادلات المطلوبة Note: RGI-A AGO=A المحاولات الموجودة Comparator A>B(G)=RB A=B (E)= AB + AB = AGB ATB (L) AB >Aizo =A01=A AI=A Λ ABX AGB- AB+AB S=AB+AB =AO B AB = AB = Co V H.W:- Design F.A, using Comparators only.

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I need an explanation of the example, solving the second question, and the Full Adder circuit in the second image.
2-Full Adder CFA)
Application for the H.A. are limited. The H.A is no
Sufficient
for adding more than two one-bit numbers. Full Adder is a logic
circuit that can add 3- bit and have two outputs. These outputs are
the sum of three bits inputs and the second output is carry of
them. The truth table and the block diagram are shown below:-
RBC
SG
-S (sum)
00
0
FA
00
Cin
-C (carry out)
0
-Carry input
-0-00 -
From the truth table:-
S=1,2,4,7
=
ABC ABC ABC + ABCin
=ACBcin+B+ A (Bar+ Bcin)
= Ā (B@ Cin) + A(B@Cin)
= Ŕ (B @ Cin) + R (B&Cin)
S = ABB Cin
Co= {3,5,6,7
=
=
ABCin+ABCin+ ABCin + ABC
ABC Cint Cin)+ Cin (AB+AB)
= AB+
Ch(AGB)
Cin=
Cin
Co
Transcribed Image Text:2-Full Adder CFA) Application for the H.A. are limited. The H.A is no Sufficient for adding more than two one-bit numbers. Full Adder is a logic circuit that can add 3- bit and have two outputs. These outputs are the sum of three bits inputs and the second output is carry of them. The truth table and the block diagram are shown below:- RBC SG -S (sum) 00 0 FA 00 Cin -C (carry out) 0 -Carry input -0-00 - From the truth table:- S=1,2,4,7 = ABC ABC ABC + ABCin =ACBcin+B+ A (Bar+ Bcin) = Ā (B@ Cin) + A(B@Cin) = Ŕ (B @ Cin) + R (B&Cin) S = ABB Cin Co= {3,5,6,7 = = ABCin+ABCin+ ABCin + ABC ABC Cint Cin)+ Cin (AB+AB) = AB+ Ch(AGB) Cin= Cin Co
EX:- Design H.A. using Comparators only:-
Solution: HA
S-AB+ AB- AB
B = AØB ]
C. AB
المعادلات
المطلوبة
Note:
RGI-A
AGO=A
المحاولات الموجودة
Comparator
A>B(G)=RB
A=B (E)= AB + AB = AGB
ATB (L) AB
>Aizo
=A01=A
AI=A
Λ
ABX
AGB- AB+AB
S=AB+AB
=AO B
AB
= AB = Co
V
H.W:- Design F.A, using Comparators only.
Transcribed Image Text:EX:- Design H.A. using Comparators only:- Solution: HA S-AB+ AB- AB B = AØB ] C. AB المعادلات المطلوبة Note: RGI-A AGO=A المحاولات الموجودة Comparator A>B(G)=RB A=B (E)= AB + AB = AGB ATB (L) AB >Aizo =A01=A AI=A Λ ABX AGB- AB+AB S=AB+AB =AO B AB = AB = Co V H.W:- Design F.A, using Comparators only.
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