Ex Convert the piping system to an equivalent length of 6" pipe. Factors K Strainer B 12" Bends C, F (each) 12" Tee D 12" Valve E 12" x 6" Cross G(xVE 12g) = 0.7 6" Meter H 6" Bends J, K (each) 6" Valve L 8.0 0.5 0.7 D %3D 1.0 150'-12"( f=0.025)- = 6.0 %3D 100- 6"(f - 0.020) 0.5 %3D = 3.0
Ex Convert the piping system to an equivalent length of 6" pipe. Factors K Strainer B 12" Bends C, F (each) 12" Tee D 12" Valve E 12" x 6" Cross G(xVE 12g) = 0.7 6" Meter H 6" Bends J, K (each) 6" Valve L 8.0 0.5 0.7 D %3D 1.0 150'-12"( f=0.025)- = 6.0 %3D 100- 6"(f - 0.020) 0.5 %3D = 3.0
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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![Ex Convert the piping system to an equivalent length of 6"
pipe.
Factors K
Strainer B
12" Bends C, F (each)
12" Tee D
= 8.0
= 0.5
= 0.7
= 1.0
12" x 6" Cross G(xV /2g) = 0.7
= 6.0
= 0.5
= 3.0
12" Valve E
150-12"(f=0.025)-
6" Meter H
6" Bends J, K (each)
6" Valve L
100-6"(f= 0.020)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fefb4dc3c-0a91-413e-8833-69342f095b7b%2F55a16f75-705b-4149-8b33-b324262e2be0%2Fgwtv95v_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Ex Convert the piping system to an equivalent length of 6"
pipe.
Factors K
Strainer B
12" Bends C, F (each)
12" Tee D
= 8.0
= 0.5
= 0.7
= 1.0
12" x 6" Cross G(xV /2g) = 0.7
= 6.0
= 0.5
= 3.0
12" Valve E
150-12"(f=0.025)-
6" Meter H
6" Bends J, K (each)
6" Valve L
100-6"(f= 0.020)
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