Ex 14. Will magnesium shavings dissolve if added to an aqueous solution of ferrous sulphate? Justify your answer! pºMg2+/Mg = -2,714 V; ºFe2+/Fe = -0,44 V a/ Yes, because Mg is a stronger oxidant than Fe b/ Yes, because Mg is a stronger reducer than Fe c/ No, because Mg is a weaker reducer than Fe d/ No, because Mg is a weaker oxidant than Fe

Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Ex 14. Will magnesium shavings dissolve if added to an aqueous
solution of ferrous sulphate? Justify your answer!
Mg2+/Mg = -2,714 V; ºFe2+/Fe = -0,44 V
a/ Yes, because Mg is a stronger oxidant than Fe
b/ Yes, because Mg is a stronger reducer than Fe
c/ No, because Mg is a weaker reducer than Fe
d/ No, because Mg is a weaker oxidant than Fe
Ex 15. Determine the type of each of the electrodes depending on
the type of potential-determining ions and write down the Nernst
equation for calculating their electrode potential:
a) Ag/AgCl, KCl
b) Pt, H₂/HCl (a=1).
c) Fe/Fe(NO3)
d) Pt/Co²+,Co³+.
Justify your answer!
Transcribed Image Text:Ex 14. Will magnesium shavings dissolve if added to an aqueous solution of ferrous sulphate? Justify your answer! Mg2+/Mg = -2,714 V; ºFe2+/Fe = -0,44 V a/ Yes, because Mg is a stronger oxidant than Fe b/ Yes, because Mg is a stronger reducer than Fe c/ No, because Mg is a weaker reducer than Fe d/ No, because Mg is a weaker oxidant than Fe Ex 15. Determine the type of each of the electrodes depending on the type of potential-determining ions and write down the Nernst equation for calculating their electrode potential: a) Ag/AgCl, KCl b) Pt, H₂/HCl (a=1). c) Fe/Fe(NO3) d) Pt/Co²+,Co³+. Justify your answer!
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